我尝试使用urllib.request.open函数打开此网页: " https://prenotaonline.esteri.it/login.aspx?cidsede=100001&returnUrl=//"
我可以使用常规浏览器访问此网页,仍然使用urrlib.request.open函数返回HTTP错误404:
import urllib.request
page = urllib.request.urlopen("https://prenotaonline.esteri.it/login.aspx?cidsede=100001&returnUrl=//").read()
print(page)
我收到以下错误:
Traceback (most recent call last):
File "/Users/markmouawad/Documents/consu_programa/scrapper.py", line 4, in <module>
page = urllib.request.urlopen("https://prenotaonline.esteri.it/login.aspx?cidsede=100001&returnUrl=//").read()
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 163, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 472, in open
response = meth(req, response)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 582, in http_response
'http', request, response, code, msg, hdrs)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 510, in error
return self._call_chain(*args)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 444, in _call_chain
result = func(*args)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 590, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 404: Not Found
我正在使用Python 3.5.3
答案 0 :(得分:0)
这是制作蜘蛛/爬行机器人时遇到的第一件事。
检测机器人的基本方法是请求标头包含User-Agent
标头。
试试这段代码:
import requests
headers = {'USER-AGENT': 'Mozilla/5.0 (iPad; U; CPU OS 3_2_1 like Mac OS X; en-us) AppleWebKit/531.21.10 (KHTML, like Gecko) Mobile/7B405'}
r = requests.get(URL, headers=headers)
print r.status_code # should be 200
print r.content # should hold page content