Question

如何使用参数int n声明数组的范围。例如，如果n = 5，我希望我的数组等于5索引。但是，就像您在我的主要内容中看到的那样，我有点手动对其进行了初始化。我只是不想在主要方面这样做。我只想声明n为5或10或其他任何值。

我知道这是一个简单的代码，但是我真的很想知道如何将数组作为参数传递而无需“手动”或像在主函数中那样。

#include <iostream>
using namespace std;

void printArray(int arr[], int n){

    // please do not change above this line

    /* Instruction 1: You will write a loop to print the content of the array arr passed into this function.
    //                There should be only one space after each integer you print and there must be only one newline
    //                at the end of printing all the numbers. n being the number of elements in arr
    //                So, just for example: if arr contains [10, 20, 30, 40, 50] then n = 5 and your loop should print
    //                10 20 30 40 50
    //                There should be a newline at the end of the above line when printed.

    */  Write your code below reading the instruction above
    for (int i = 0; i < n; ++i)
        {
            cout << arr[i] << " ";
        }
    cout << endl;




}


// Initialised the arr with 5 here but i want n to be the range of 
//my array 
int main()
{
    int arr[5] = {1,2,3,4,5} ;
    printArray(arr, 5);

}

调用数组作为参数-C ++

0 个答案: