Question

我很难从要在python中解析的文件的句子开头删除此"//!"。

with open("dwe.txt", "r") as file1:
    for row in file1:
        print(row.rstrip('//!'))

预期产量

The flag should not process everything that was given at the time 
it was processing.

实际输出

//! The flag should not process everything that was given at the time 
//! it was processing.

Answer 1

如@Kevin所述，rstrip()，lstrip()和strip()删除了所包含字符串的所有变体，直到遇到不匹配的字符为止，因此对于您的操作而言并不理想。例如：

>>> 'barmitzvah'.lstrip('bar')
'mitzvah'
>>> 'rabbit'.lstrip('bar')
'it'
>>>'rabbarabbadoo'.lstrip('bar')
'doo'

尝试改用startswith()：

with open("dwe.txt", "r") as file1: 
    for row in file1.readlines(): 
        if row.startswith('//! '):
            print(row[3:])

Answer 2

在@Adam评论中，您只需将rstrip更改为lstrip：

with open("dwe.txt", "r") as file1: 
     for row in file1: print(row.rstrip('//!'))

>  The flag should not process everything that was given at the time //! it was processing.

如何从python中的文件中删除符号？

2 个答案: