Question

如果y包含x的最后一个单词，我想用y替换x的最后一个单词。我该如何处理？

let x ='jaguar lion tiger panda'
let y = 'pandas'

预期结果：

'jaguar lion tiger pandas'

如果

y = 'cat'

预期结果：

'jaguar lion tiger panda cat'

我尝试过的代码：

console.log(response)
let before = this.text.split(' ')
console.log(before)
console.log(before.length)
let a = before.slice(before.length-1)
console.log(a)
if (response.data.text[0].includes(a)) {
  let x = (before.slice(0, before.length-1))
  let y = x.replace(',', ' ')
  this.preResult = y.push(response.data.text[0])
} else {
  this.preResult.push(this.text + ' ' + response.data.text[0])

Answer 1

您可以使用正则表达式匹配最后一个单词，然后通过检查单词y includes来进行测试。如果是这样，请用y替换该单词，否则请替换为与y串联的原始单词：

const x ='jaguar lion tiger panda'

const doReplace = y => x.replace(
  /\S+$/, // match non-space characters, followed by the end of the string
  (word) => (
    y.includes(word)
    ? y
    : word + ' ' + y
  )
);
console.log(doReplace('pandas'));
console.log(doReplace('cat'));

Answer 2

另一种解决方案：

    let x ='jaguar lion tiger panda'
    let y = 'pandas'
    let splited = x.split(' ')
    let lastWord = splited[splited.length - 1]
    
    if(y.indexOf(lastWord) >= 0){
        splited[splited.length - 1] = y
    }else{
        splited.push(y)
    }
    
    let result = splited.join(' ')
    console.log(result)

Answer 3

function replaceLastWord(x, y) {
    let result = x.split(' '), lastIndex = (result.length || 1) - 1, lastWord = result[lastIndex]
    result[lastIndex] = y.indexOf(lastWord) !== -1 ?  y : `${lastWord} ${y}`
    return result.join(' ')
}

console.log(replaceLastWord('jaguar lion tiger panda', 'pandas'))
console.log(replaceLastWord('jaguar lion tiger panda', 'cat'))
console.log(replaceLastWord('', 'pandas'))

在某些情况下，用另一个字符串替换一个字符串

3 个答案: