Question

我试图替换字符串中的某些单词，因此我们有一个编码字符串：

%3Cscript%20async%20src%3D%22%2F%2Fpagead2.googlesyndication.com%2F%25dontreplace%25%2Fjs%2Fadsbygoogle.js%22%3E%3C%2Fscript%3E%0A%3Cins%20class%3D%E2%80%9C%25dontreplace%25%22%0Astyle%3D%22display%3Ainline-block%3Bwidth%3A300px%3Bheight%3A250px%22%0Adata-ad-client%3D%22ca-pub-xxxxxxxxxxxxxxxxxxxx%22%0Adata-ad-slot%3D%22yyyyyyyyyyyy%E2%80%9D%3E%0Aparams%20%3D%20%7B%0Apuid1%3A%E2%80%99%25replace1%25%E2%80%99%2C%0Apuid2%3A%E2%80%99%25replace2%25%27%2C%0Apuid3%3A%27%25replace3%25%27%0A%0A%7D

其中有几句话：

%25dontreplace%25
%25dontreplace%25
%25replace1%25
%25replace2%25
%25replace3%25

我需要将所有%25replaceX%25替换为%replaceX%，但不要触及所有%25dontreplace%25（每个var x = "%3Cscript%20async%20src%3D%22%2F%2Fpagead2.googlesyndication.com%2F%25dontreplace%25%2Fjs%2Fadsbygoogle.js%22%3E%3C%2Fscript%3E%0A%3Cins%20class%3D%E2%80%9C%25dontreplace%25%22%0Astyle%3D%22display%3Ainline-block%3Bwidth%3A300px%3Bheight%3A250px%22%0Adata-ad-client%3D%22ca-pub-xxxxxxxxxxxxxxxxxxxx%22%0Adata-ad-slot%3D%22yyyyyyyyyyyy%E2%80%9D%3E%0Aparams%20%3D%20%7B%0Apuid1%3A%E2%80%99%25replace1%25%E2%80%99%2C%0Apuid2%3A%E2%80%99%25replace2%25%27%2C%0Apuid3%3A%27%25replace3%25%27%0A%0A%7D"; console.log(x); var y = x.split(/(%25)/); console.log(y); var n = []; for (var i = 0; i <= y.length; i++) { if (y[i].indexOf('%25') >= 0) { if (y[i + 1].indexOf('request.puid') >= 0) { n.push('%'+y[i]+'%'); console.log(n); } } else { if (y[i - 1] === undefined && y[i + 1] === '%25') { n.push(y[i]); console.log(n); } else if (y[i - 1] === '%25' && y[i + 1] === undefined) { n.push(y[i]); console.log(n); } else if (y[i - 1] === '%25' && y[i + 1] === '%25') { n.push('%25'+y[i]+'%25'); console.log(n); } } }可以有不同的数量）

我试图将它拆分成阵列并做一些ifelse陈述，但它似乎不起作用，我认为它不是最优雅的：

＆＃13;

@Override
public void onBindViewHolder(final AdapterHolder holder, final int position) {
    final Item_GetMembers item_getMembers = CategoriesList.get(position);
    //It means if your position is zero then zero position item will move at third position
    if(position == 0)
       moveItem(3, item_getMembers);

}

private void moveItem(int toItemPos, Item_GetMembers item)
{
   for(int i = 0; i < CategoriesList.size(); i++){
        if(toItemPos == i){
            CategoriesList.add(i, item)
            break;              
        }
   }
   notifyDataSetChanged();
}

＆＃13;

有没有一种优雅的方法来解决这个问题？

Answer 1

您可以使用.replace使用捕获组RegExp。

我们使用的RegExp是RegExp(/%25replace([0-9]*)%25/, 'g')，它会找到与%25replaceX%25匹配的字符串，而g会找到所有匹配项。 ()捕获数字，以便我们可以在替换文本中使用它。

这样的事情：

＆＃13;

var str = "%3Cscript%20async%20src%3D%22%2F%2Fpagead2.googlesyndication.com%2F%25dontreplace%25%2Fjs%2Fadsbygoogle.js%22%3E%3C%2Fscript%3E%0A%3Cins%20class%3D%E2%80%9C%25dontreplace%25%22%0Astyle%3D%22display%3Ainline-block%3Bwidth%3A300px%3Bheight%3A250px%22%0Adata-ad-client%3D%22ca-pub-xxxxxxxxxxxxxxxxxxxx%22%0Adata-ad-slot%3D%22yyyyyyyyyyyy%E2%80%9D%3E%0Aparams%20%3D%20%7B%0Apuid1%3A%E2%80%99%25replace1%25%E2%80%99%2C%0Apuid2%3A%E2%80%99%25replace2%25%27%2C%0Apuid3%3A%27%25replace3%25%27%0A%0A%7D";

var newStr = str.replace(new RegExp(/%25replace([0-9]*)%25/, 'g'), "%replace$1%");

document.write(newStr)

＆＃13;

替换字符串中的一些单词，但保留另一个

1 个答案: