因此，我正在制作simon所说的游戏，但我无法让用户单击颜色，以便游戏可以查看用户单击的内容是否正确。
现在，我已经为按钮实现了onclick方法。目的是当用户单击按钮一定次数时，游戏将检查显示的图案是否与用户提供的图案相同。游戏显示出良好的图案。但是，在游戏显示了模式之后单击按钮会导致游戏停止工作。我尝试运行调试器，但是当我执行该操作时，该活动将无法加载，因此我实际上无法单击该按钮。但是当我刚运行游戏时，活动显示，但是当我单击按钮时崩溃。
这是创建时的
public class MainActivity extends AppCompatActivity implements View.OnClickListener {
int[] pattern;
int[] guess;
Button[] colours;
public int count;
public TextView Final;
public int score;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Button green = findViewById(R.id.Green);
Button blue = findViewById(R.id.Blue);
Button red = findViewById(R.id.Red);
Button purple = findViewById(R.id.purple);
TextView Final = findViewById(R.id.Score);
colours = new Button[]{green, blue, red, purple};
int score = 0;
do {
pattern = showPattern(colours, score);
guess = getGuess(colours, score);
}while(Arrays.equals(pattern,guess));
Final.setText("Score is" + score);
}
这是onclick方法：
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.Green:
guess[count] = 0;
count++;
if (count >= score + 1 && Arrays.equals(pattern,guess)) {
score++;
pattern = showPattern(colours,score);
count = 0;
}
else if (count>=score + 1) {
String result = "You're score is " + score;
Final.setText(result);
}
case R.id.Blue:
guess[count] = 1;
count++;
if (count >= score + 1 && Arrays.equals(pattern,guess)) {
score++;
pattern = showPattern(colours,score);
count = 0;
}
else if (count>=score + 1) {
String result = "You're score is " + score;
Final.setText(result);
}
case R.id.Red:
guess[count] =2;
count++;
if (count >= score + 1 && Arrays.equals(pattern,guess)) {
score++;
pattern = showPattern(colours,score);
count = 0;
}
else if (count>=score + 1) {
String result = "You're score is " + score;
Final.setText(result);
}
case R.id.purple:
guess[count] = 3;
count++;
if (count >= score + 1 && Arrays.equals(pattern,guess)) {
score++;
pattern = showPattern(colours,score);
count = 0;
}
else if (count>=score + 1) {
String result = "You're score is " + score;
Final.setText(result);
}
default:
break;
}
}
这是我认为导致我的应用出现问题的getGuess方法。
public int[] getGuess(Button[] colours, int score) {
guess = new int[score+1];
colours[0].setOnClickListener(this);
colours[1].setOnClickListener(this);
colours[2].setOnClickListener(this);
colours[3].setOnClickListener(this);
while(count<score+1){
}
return guess;
这是showPattern方法：
public int[] showPattern(final Button[] colours, int score) {
int[] pattern = new int[score + 1];
Random rand = new Random();
for (int j=0;j<score + 1;j++) {
pattern[j] = rand.nextInt(4);
switch (pattern[j]) {
case 0:
new CountDownTimer(2000,2000) {
public void onTick(long millisUntilFinished) {
colours[0].setBackgroundColor(getColor(R.color.lightGreen));
}
public void onFinish() {
colours[0].setBackgroundColor(getColor(R.color.green));
}
}.start();
break;
case 1:
new CountDownTimer(2000,2000) {
public void onTick(long millisUntilFinished) {
colours[1].setBackgroundColor(getColor(R.color.lightBlue));
}
public void onFinish() {
colours[1].setBackgroundColor(getColor(R.color.blue));
}
}.start();
break;
case 2:
new CountDownTimer(2000,2000) {
public void onTick(long millisUntilFinished) {
colours[2].setBackgroundColor(getColor(R.color.lightRed));
}
public void onFinish() {
colours[2].setBackgroundColor(getColor(R.color.red));
}
}.start();
break;
case 3:
new CountDownTimer(2000,2000) {
public void onTick(long millisUntilFinished) {
colours[3].setBackgroundColor(getColor(R.color.lightPurple));
}
public void onFinish() {
colours[3].setBackgroundColor(getColor(R.color.purple));
}
}.start();
break;
}
}
return pattern;
}
我期望一旦公共变量计数等于超出的变量分数，并且猜测和模式数组都相等，那么我就可以显示模式并等待用户再次猜测。但是，一旦单击按钮，游戏就会停止。
（UPDATE）因此，我认为除了getguess方法之外，do while循环似乎也在弄乱我的代码。另外，logcat的最后一行读取为
Accessing hidden method Landroid/view/ViewGroup;->makeOptionalFitsSystemWindows()V (light greylist, reflection)