我正在使用Excel在Data Frame上的Timegrouper上工作,并尝试使用Date作为列标题,将Time作为行,Y上的总计数为“ Barton LLC”来执行Pviot。
Data.xls
X Y Z D
740150 Barton LLC B1-20000 2014-01-01 02:21:51
740150 Barton LLC B1-50809 2014-01-01 02:21:51
740150 Barton LLC B1-53102 2014-01-01 02:21:51
740150 Barton LLC S2-16558 2014-01-02 21:21:01
740150 Barton LLC B1-86481 2014-01-02 21:21:01
740150 Curlis L S1-06532 2014-01-02 21:21:01
740150 Barton LLC S1-47412 2014-01-02 21:21:01
740150 Barton LLC B1-33364 2014-01-02 21:21:01
740150 Barton LLC S1-93683 2014-02-07 04:34:50
740150 Barton LLC S2-10342 2014-02-07 04:34:50
尝试使用重采样,数据透视和时间分组器,但出现了错误序列
import pandas as pd
import numpy as np
df = pd.read_excel("data.xlsx")
ndf = df[df['Type'].eq('df')].pivot_table(columns= ['Y'],values='Y',
index=pd.Grouper(key='D',freq='H'),aggfunc='count',fill_value=0)
结果
2014-01-01,2014-01-02,2014-02-07
02:21 3,NaN,NaN
21:21 NaN,4,NaN
04:34 NaN,NaN,2
答案 0 :(得分:3)
您可以将datetime
和date
中的time
列分开并使用pivot_table
:
df['date'] = df['D'].dt.date
df['time'] = df['D'].dt.time
pd.pivot_table(df, 'D', 'time', 'date', aggfunc='count')
date 2014-01-01 2014-01-02 2014-02-07
time
02:21:51 3.0 NaN NaN
04:34:50 NaN NaN 2.0
21:21:01 NaN 5.0 NaN
请注意,您在日期2014-01-02 21:21:01
缺少一个计数
答案 1 :(得分:1)
使用crosstab
和strftime
将datetime
转换为自定义字符串:
df.D = pd.to_datetime(df.D)
ndf = pd.crosstab(df['D'].dt.strftime('%H:%M').rename('H'), df['D'].dt.strftime('%Y-%m-%d'))
print (ndf)
D 2014-01-01 2014-01-02 2014-02-07
H
02:21 3 0 0
04:34 0 0 2
21:21 0 5 0
ndf = pd.crosstab(df['D'].dt.time.rename('T'), df['D'].dt.date)
print (ndf)
D 2014-01-01 2014-01-02 2014-02-07
T
02:21:51 3 0 0
04:34:50 0 0 2
21:21:01 0 5 0