Question

我想构建一个不使用字典库的简单字典搜索程序。如果数组中的字符串等于char数组，我想搜索字符串数组。它应该打印字符串及其索引号。如果有两个与char匹配的字符串，则它应打印第一个字符串，并保留后一个字符串

.e.g字符串array [“ fine”，“ rest”，“ door”，“ shine”]字符[[t'，'r'，'e'，'s']。答案应该是索引1处的“ rest”。如果重复String Rest，那么它应该只打印第一个。

我试图比较字符串数组和char数组，但是它返回了与char数组匹配的字符串数组的所有单词。

String strArray[]=new String[4];
char chrArray[]=new char[4]; 
String value="";
char compare;
System.out.println("Enter the words :");
    for(int i=0;i<strArray.length;i++){
    strArray[i]=input.next();

    } 
    System.out.println("Enter the Characters :");
    for (int i = 0; i < chrArray.length; i++) {
        chrArray[i]=input.next().charAt(0);

    }

    for (int i = 0; i < strArray.length; i++) {
            if(strArray[i].length()==chrArray.length){
                 if(""+strArray[i]!=value){
               value="";
            }
        for (int j = 0; j < strArray[i].length(); j++) {

            for (int k = 0; k < chrArray.length; k++) {


                if(strArray[i].charAt(j)==chrArray[k]){
                value=value+strArray[i].charAt(j);   

                }
            }
            }
        }

}
        System.out.println(value);

输出应为来自数组的字符串，该字符串等于char数组。

Answer 1

您可以对char数组进行排序，然后使用Arrays.equal对其进行比较。通过对char数组进行排序，将不需要为循环使用2。

import java.util.Arrays;
import java.util.Scanner;

public class Bug {

        public static void main(String[] args) {
            String strArray[]=new String[4];
            char chrArray[]=new char[4];
            Scanner input = new Scanner(System.in);
            System.out.println("Enter the words :");
            for(int i=0;i<strArray.length;i++){
                strArray[i]=input.next();

            }
            System.out.println("Enter the Characters :");
            for (int i = 0; i < chrArray.length; i++) {
                chrArray[i]=input.next().charAt(0);

            }
            Arrays.sort(chrArray);

            for (int i = 0; i < strArray.length; i++) {
                char[] x = strArray[i].toCharArray();
                Arrays.sort(x);
                if(Arrays.equals(chrArray, x))
                {
                    System.out.println(strArray[i]);
                    break;
                }
            }
        }

 }

Answer 2

您还可以创建一个Map<Character, Integer>来存储单词和字符的计数，并将每个单词的字符计数与字符计数进行比较。如果两者相等，则将其打印出来。

演示：

import java.util.Map;
import java.util.HashMap;

public class Example {
    private static final String[] words = {"fine", "rest", "door", "shine"};
    private static final char[] chars = {'t', 'r', 'e', 's'};

    /**
     * Initialise String character counts in a hashmap datastructure.
     * @param word The string word to iterate.
     * @return Hashmap of character -> counts.
     */
    private static Map<Character, Integer> getCharCounts(String word) {
        Map<Character, Integer> wordCounts = new HashMap<>();

        for (int i = 0; i < word.length(); i++) {
            Character character = word.charAt(i);

            // If key doesn't exist, initialise it
            if (!wordCounts.containsKey(character)) {
                wordCounts.put(character, 0);
            }

            // Increment count by 1
            wordCounts.put(character, wordCounts.get(character) + 1);
        }

        return wordCounts;
    }

    public static void main(String[] args) {     
        // Initialise character counts first
        Map<Character, Integer> charCounts = getCharCounts(String.valueOf(chars));

        for (int i = 0; i < words.length; i++) {
            Map<Character, Integer> wordCounts = getCharCounts(words[i]);

            // If Hashmaps are equal, then we have found a match
            if (wordCounts.equals(charCounts)) {
                System.out.println(words[i] + ", at index = " + i);
                break;
            }
        }
    }
}

输出：

rest, at index = 1

如何通过char数组搜索String数组？

2 个答案: