Question

我有一个包含ID，路径和文件名的字符串数组。它们都用分号分隔，它看起来像这样：

1.235.554; C：\ somewhere \ somewhere \这是doc.txt的名称;这是doc的名称

我的代码如下：

//string array already has data
string[] file_final;

//gets height to find array size
int height = file_final.GetLength(0);

//declares 2d array
string[,] table = new string[height, 3];     

for(int i = 0; i < height; i++){ //loops until height is hit
            foreach(char c in file_final[i]) //checks each char in line[i]
            {
                if(c != ';'){ //if not ; then
                   string temp; //I would like to save each char into this string
                   //temp = temp append/insert/+ didnt work
                   // I know data conversion from char to string is an issue                                
                }
                else
                {
                }
            }

     }

我想要的输出是：

[0,0] = 1.235.554（ID）

[0,1] = C：\ somewhere \ somewhere \这是doc.txt（Path）的名称

[0,2] =这是doc（文件名）
的名称

依此类推，直到我们用完文件中的行来阅读。

我遇到char到string的问题，我知道这是两种不同的数据类型，但我认为append会起作用。我应该保存每个字符，直到我的临时字符串中的半冒号，然后将其添加到数组，清除我的字符串，继续读取该行的其余部分，增加我的数组索引然后再次保存，直到行结束？

Answer 1

如果您可以将数据存储在string[][]而不是string[,]，

使用System.Linq

string[][] table = File.ReadAllLines(filePath)
                       .Select(line => line.Split(';'))
                       .ToArray();

如果您确实需要将数据存储在多维数组中，可以使用此扩展方法将锯齿状数组转换为二维数组：

public static TSource[,] To2D<TSource>(this TSource[][] jaggedArray)
{
    int firstDimension = jaggedArray.Length;
    int secondDimension = jaggedArray.GroupBy(row => row.Length).Single().Key;

    TSource[,] result = new TSource[firstDimension, secondDimension];
    for (int i = 0; i < firstDimension; ++i)
        for (int j = 0; j < secondDimension; ++j)
           result[i, j] = jaggedArray[i][j];

    return result;
}

然后您将拥有以下代码：

string[,] table = File.ReadAllLines(filePath)
                      .Select(line => line.Split(';'))
                      .ToArray()
                      .To2D();

Answer 2

Hello user5468794因为我没有很好地解释它。让我举一个例子。

首先创建一个ID对象......

class IDObject
{
  private string id;
  private string path;
  private string fName;
  //public properties
  public string Id
  {
    get { return id; }
    set { id = value; }
  }

  public string Path
  {
    get { return path; }
    set { path = value; }
  }
  public string FName
  {
    get { return fName; }
    set { fName = value; }
  }
  // constructor
  public IDObject(string inID, string inPath, string inFName)
  {
    id = inID;
    path = inPath;
    fName = inFName;
  }

然后在Main

public Form1()
{
  InitializeComponent();

  // since you have an array of the strings...
  List<string> allStrings = getSomeStrings(); // you do not specify how you get these string
  List<IDObject> arrayOfAll_IDObjects = new List<IDObject>();

  foreach (string curString in allStrings)
  {
    string[] splitStringArray = curString.Split(';');
    IDObject curIDObj = new IDObject(splitStringArray[0], splitStringArray[1], splitStringArray[2]);
    arrayOfAll_IDObjects.Add(curIDObj);
  }

  // now you have a single array of the IDObjects
  // you can loop thru it and make your 2 dimensional array if needed

  int row = 0;
  string[,] twoDimArray = new string[arrayOfAll_IDObjects.Count, 3];

  foreach (IDObject curID in arrayOfAll_IDObjects)
  {
    twoDimArray[row, 0] = curID.Id;
    twoDimArray[row, 1] = curID.Path;
    twoDimArray[row, 2] = curID.FName;
    row++;
  }
}

  private List<string> getSomeStrings()
  {
    List<string> allStrings = new List<string>();
    allStrings.Add(@"1.235.554;C:\somewhere\somewhere\this is name of doc.txt;this is name of doc");
    allStrings.Add(@"2.235.554;C:\somewhere\somewhere\this is name of doc.txt;this is name of doc");
    allStrings.Add(@"3.235.554;C:\somewhere\somewhere\this is name of doc.txt;this is name of doc");
    allStrings.Add(@"4.235.554;C:\somewhere\somewhere\this is name of doc.txt;this is name of doc");
    allStrings.Add(@"5.235.554;C:\somewhere\somewhere\this is name of doc.txt;this is name of doc");
    return allStrings;
  }

希望这有帮助。

字符串数组通过字符串运行直到char然后保存到2D数组

2 个答案: