我有一个看起来像这样的数组-
var myOldArray = [{
"id": 1,
"form_id": 4,
"form_field_name": "field_1",
"helperTitle": "This is Box 1's TItle",
"helperText": "This is Box 1 data",
"created_at": null,
"updated_at": null
},
{
"id": 2,
"form_id": 4,
"form_field_name": "field_2",
"helperTitle": "Box 2 Title",
"helperText": "Box 2 TExt",
"created_at": null,
"updated_at": null
}
]
我需要将数组复制/复制/转换/ ...到这样的东西-
myNewArray = {
field_1['title'] = "This is Box 1's Title",
field_1['text'] = "This is Box 1 data",
field_2['title'] = "Box 2 Title",
field_2['text'] = "Box 2 Text",
}
以便我可以参考
console.log(myNewArray.field_1.title)
或更有用的东西。
我尝试使用过滤器方法无济于事。我尝试过的一切都返回未定义。我只是超级困惑。是否有更好的方法直接引用子数组中的元素而不进行转换?
这有点工作... console.log将输出我想要的内容,但是返回值将输出为undefined,这使我感到困惑。
myOldArray = [{
"id": 1,
"form_id": 4,
"form_field_name": "field_1",
"helperTitle": "This is Box 1's TItle",
"helperText": "This is Box 1 data",
"created_at": null,
"updated_at": null
},
{
"id": 2,
"form_id": 4,
"form_field_name": "field_2",
"helperTitle": "Box 2 Title",
"helperText": "Box 2 TExt",
"created_at": null,
"updated_at": null
}
]
var AR = myOldArray;
var newArr = AR.filter(function(item) {
if (item.form_field_name == fieldName) {
console.log('txt - ' + item + '\n\n');
return item;
}
});
答案 0 :(得分:0)
您可以将所需属性作为对象映射到新对象中。
它与
一起使用Array#map
映射数组的对象,field
返回带有另一个具有重命名属性的对象的新对象,Object.assign
和spread syntax ...
将所有新对象分配到单个对象
var data = [{ id: 1, form_id: 4, form_field_name: "field_1", helperTitle: "This is Box 1's TItle", helperText: "This is Box 1 data", created_at: null, updated_at: null }, { id: 2, form_id: 4, form_field_name: "field_2", helperTitle: "Box 2 Title", helperText: "Box 2 TExt", created_at: null, updated_at: null }],
result = Object.assign(
...data.map(({ id, helperTitle: title, helperText: text }) =>
({ ['field_' + id]: { title, text } }))
);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
答案 1 :(得分:0)
我猜所有的处理都应该在$ .get函数中:
$.getJSON('/api/system/formHelperText/4', function (data) {
var myNewArray = data.map(function(item) {
var obj = {};
obj['field_' + item.id] = { Title: item.helperTitle, Text: item.helperText };
return obj;
});
console.log(myNewArray);
};
答案 2 :(得分:0)
您可以编写一个简单的reduce
调用以获取所需的输出:
const array=[{id:1,form_id:4,form_field_name:"field_1",helperTitle:"This is Box 1's TItle",helperText:"This is Box 1 data",created_at:null,updated_at:null},{id:2,form_id:4,form_field_name:"field_2",helperTitle:"Box 2 Title",helperText:"Box 2 TExt",created_at:null,updated_at:null}]
const result= array.reduce((acc, a) =>
(acc[a.form_field_name] = {title: a.helperTitle,text: a.helperText}, acc), {});
console.log(result);
答案 3 :(得分:0)
答案很简单:
const objs = new Map();
for (const obj of myOldArray) {
objs.set(obj.form_field_name, obj);
}
现在您可以通过字段名称访问对象:
const myObj = objs.get("field_1");