我有以下对象结构
var obj = {"0":"direct","1":"indirect","2":"dir","3":"indir"};
预期输出为:
result = [["direct","indirect"],["indirect","dir"],["dir","indir"]];
我尝试过:
var result = [];
var array = [];
for(var key in obj){
if(array.length <2) {
array.push(obj[key]);
}else{
array =[];
array.push(obj[key-1]);
}
if(array.length == 2){
result.push(array);
}
}
console.log(result);
我得到的输出如下:
result = [["direct", "indirect"], ["indirect", "indir"]]
答案 0 :(得分:2)
如果它们都是至少包含一个字符的字符串,那么你可以这样做:
var obj = {"0":"direct","1":"indirect","2":"dir","3":"indir"};
var result = [];
for (var i = 1; obj[i]; i++) {
result.push([obj[i-1], obj[i]]);
}
从索引1
开始,并推送数组中的当前和前一项。只要值是真实的,它就会继续,所以如果有一个空字符串,它就会停止。
如果可能存在需要包含的假值,则应首先计算属性。
var obj = {"0":"direct","1":"indirect","2":"dir","3":"indir"};
var result = [];
var len = Object.keys(obj).length;
for (var i = 1; i < len; i++) {
result.push([obj[i-1], obj[i]]);
}