Question

我无法通过for循环为原始绘制的矩形充气。我可能想将原始绘制的矩形存储到数组中，并从它们的循环中将其存储，但无法正常工作。

 loop_txtbx.Text = 5
 parameter_txtbx.Text = 20

 int[] rec = new int[loops];

 int xCenter = Convert.ToInt32(startX_coord_txtbx.Text);
 int yCenter = Convert.ToInt32(startY_coord_txtbx.Text); 

 int width = Convert.ToInt32(width_txtbx.Text);
 int height = Convert.ToInt32(height_txtbx.Text);

 //Find the x-coordinate of the upper-left corner of the rectangle to draw.
  int x = xCenter - width / 2;

 //Find y-coordinate of the upper-left corner of the rectangle to draw. 
  int y = yCenter - height / 2;

  int loops = Convert.ToInt32(loop_txtbx.Text);
  int param = Convert.ToInt32(parameter_txtbx.Text);

   // Create a rectangle.
  Rectangle rec1 = new Rectangle(x, y, width, height);

   // Draw the uninflated rectangle to screen.
  gdrawArea.DrawRectangle(color_pen, rec1);   

  for (int i = 0; i < loops; i++)
      {

      // Call Inflate.
      Rectangle rec2 = Rectangle.Inflate(rec1, param, param);

      // Draw the inflated rectangle to screen.
      gdrawArea.DrawRectangle(color_pen, rec2);
      }

仅显示了2个绘制的矩形，而应该是5个。我无法修改rec2

Answer 1

您使用相同的rec1作为基础进行充气。因此，在第一个循环之后，新矩形的大小总是相同。

您需要使用rec2

Rectangle rec2 = rec1;
for (int i = 0; i < loops; i++)
{
    rec2 = Rectangle.Inflate(rec2, param, param);
    ....
}

但是使用这种方法，您应该反转绘制初始矩形的调用顺序

  Rectangle rec2 = rec1;
  for (int i = 0; i < loops; i++)
  {
       // Draw the current rectangle to screen.
       gdrawArea.DrawRectangle(color_pen, rec2);

       // Call Inflate.
       rec2 = Rectangle.Inflate(rec2, param, param);
  }

如何通过c＃中的for循环增加绘制矩形的大小？

1 个答案: