Question

有人知道如何确保Type的值继承自超类的Type吗？

    public class Resource {

        private Executor executor = Executors.newSingleThreadExecutor();

        @GET
        public void asyncGet(@Suspended final AsyncResponse asyncResponse) {

            asyncResponse.setTimeoutHandler(new TimeoutHandler() {
                @Override
                public void handleTimeout(AsyncResponse asyncResponse) {
                    asyncResponse.resume("Processing timeout.");
                    executor.shutdown();
                }
            });

            asyncResponse.setTimeout(60, TimeUnit.SECONDS);
            executor.submit(() -> {
                String result = someService.expensiveOperation();
                asyncResponse.resume(result);
                executor.shutdown();
            });
        }
    }

我知道如何在Java中使用：

public class MyClass {

    private Type myType;  // where the type is a subclass MySuperClass type

}

但是我想知道如何在C＃中做到这一点

Answer 1

您应在以下位置使用

：

class Myclass<Type> where Type: Superclass

文档：https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/keywords/where-generic-type-constraint

Answer 2

要回复Skaparate，这不正是我想要的。我不想在我想使用Types作为属性（例如类型列表的例子）时被迫创建一个新类

所以我创建了一个类似于java.lang.Class的类，我将在需要时添加任何方法：

public class Class<T> where T : class {
    public T newInstance()
    {
        return (T) Activator.CreateInstance(typeof(T));
    }

    public T newInstance(params object[] parameters)
    {
        return (T) Activator.CreateInstance(typeof(T), parameters);
    }

    public new Type GetType()
    {
        return typeof(T);
    }
}

public abstract class Spell {

    // as a battle animation's attributes changes during the animation I want to recreate a new one anytime this spell is used
    private Class<BattleAnimation> animation;

    public BattleAnimation GetAnimation() {
        return this.animation.newInstance();
    }

}

如何在C＃中强制类型成为另一类型的子类

2 个答案: