Question

我是Android Studios和Gradle的新手，所以如果这个问题很明显，我想道歉。

使用给定的代码时出现以下错误：

Error: Program type already present: javax.inject.Inject

apply plugin: 'com.android.application'

android {
    compileOptions {
        sourceCompatibility JavaVersion.VERSION_1_8
        targetCompatibility JavaVersion.VERSION_1_8
    }
    compileSdkVersion 28
    defaultConfig {
        applicationId "com.example.xxx.cryptoapp"
        minSdkVersion 15
        targetSdkVersion 28
        versionCode 1
        versionName "1.0"
        testInstrumentationRunner "android.support.test.runner.AndroidJUnitRunner"
    }
    buildTypes {
        release {
            minifyEnabled false
            proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
        }
    }
}

dependencies {
    implementation fileTree(dir: 'libs', include: ['*.jar'])
    implementation 'com.android.support:appcompat-v7:28.0.0'
    implementation 'com.android.support:design:28.0.0'
    implementation 'com.android.support.constraint:constraint-layout:1.1.3'
    implementation 'android.arch.lifecycle:extensions:1.1.1'
    testImplementation 'junit:junit:4.12'
    androidTestImplementation 'com.android.support.test:runner:1.0.2'
    androidTestImplementation 'com.android.support.test.espresso:espresso-core:3.0.2'
    compile 'com.lucadev:coinmarketcap-api:2.1'
}

希望您能帮助我。：）

修改

我研究了依赖关系，发现javax.inject被使用了两次：

//short version of the list
+--- org.glassfish.hk2.external:javax.inject:2.5.0-b42@jar
+--- com.fasterxml.jackson.core:jackson-core:2.8.4@jar
    \--- javax.inject:javax.inject:1@jar

但是我不太了解如何排除正确的模块。

Answer 1

假设这来自.jar目录中的libs文件；可以像这样被排除在外：

implementation (fileTree(dir: "libs", include: ["*.jar"])) {
    exclude group: "javax.inject", module: "javax.inject"
}

实际上，.jar应该应该被删除并替换为：

// https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-core
implementation ("com.fasterxml.jackson.core:jackson-core:2.9.8") {
    exclude group: "javax.inject", module: "javax.inject"
}

此存储库为mavenCentral()。

Gradle：错误：程序类型已存在：javax.inject.Inject

1 个答案: