Question

我想使用c ++中的结构创建循环缓冲区。基本实现。我在将元素插入缓冲区时遇到问题。这是我写的代码。

这是我的结构定义：

#define LENGTH_BUFFER 100
typedef struct {
  int buffer[LENGTH_BUFFER];
  int head;
  int tail;
} ringbuffer;


ringbuffer test;

初始化以将指针设置为0：

void RingBuffer_Init(ringbuffer temp)
{
  temp.head = 0;
  temp.tail = 0;
}

推送数据功能：

void RingBuffer_Push(int data,ringbuffer temp)
{
  temp.buffer[temp.head] = data;
  temp.head++;
}

在这里我调用函数来初始化和推送数据

void main()
{
  RingBuffer_Init(test);
  RingBuffer_Push(25,test);

  cout << test.buffer[0]<<endl;
}

我似乎无法将数据推送到缓冲区。请帮帮我。它返回所有零。

Answer 1

假设 head 是放置新值的索引，当您推入值temp.head++;时必须用temp.head = (temp.head + 1) % BUFFER_LENGTH;代替，以管理缓冲区的长度。当缓冲区已满时，还必须移动 tail 。

我不明白为什么要先推1个值然后写5个值

您说您使用C ++，那么为什么要用C编写？为什么在环形缓冲区上没有构造函数和push / pop / top操作？

{编辑添加}

您所要求的使用c ++的非常简单的方法

#include <iostream>
using namespace std;

#define LENGTH_BUFFER 4

// in c++ we use a struct when all members are public (by default all is public in a struct),
// but this is dangerous because all can be modified from outside without any protection,
// so I prefer to use a class with public/private parts

class RingBuffer {
  public:
    // The constructor, it replaces RingBuffer_Init,
    // The big advantage is you cannot miss to call the constructor
    RingBuffer();

    // it is not needed to have a destructor, the implicit destructor is ok

    // because it is an operation you do not have to give the ringbuffer in parameter
    void push(int data);

    // I had the print operation, it print following the order of insertion
    // to print doesn't change the instance, so I can say the operaiotn is 'const'
    void print() const;

  private:
    int buffer[LENGTH_BUFFER];
    int head; // index of the future value
    int tail; // index of the older inserted value, except if empty / head == index
};

// The buffer is initialized empty, head == tail
// I can initialize the indexes by any other valid
// value, this is not relevant
RingBuffer::RingBuffer() : head(0), tail(0) {
}

// push a new value, 
void RingBuffer::push(int data)
{
  buffer[head] = data;
  head = (head + 1) % LENGTH_BUFFER;

  if (head == tail)
    tail = (tail + 1) % LENGTH_BUFFER;
}

// print the content and indexes
void RingBuffer::print() const {
  for (int p = tail; p != head; p = (p + 1)  % LENGTH_BUFFER)
    cout << buffer[p] << ' ';
  cout << " (head=" << head << ", tail = " << tail << ')'  << endl;
}

int main()
{
  RingBuffer test;

  test.print();

  test.push(1);
  test.print();

  test.push(2);
  test.print();

  test.push(3);
  test.print();

  test.push(4);
  test.print();

  test.push(5);
  test.push(6);
  test.print();

  return 0;
}

我减小了缓冲区的大小以使其旋转很少的值。

执行产生：

 (head=0, tail = 0)
1  (head=1, tail = 0)
1 2  (head=2, tail = 0)
1 2 3  (head=3, tail = 0)
2 3 4  (head=0, tail = 1)
4 5 6  (head=2, tail = 3)

如您所见，在实现中丢失了一个条目，它的大小为4，但仅管理3个值。我让你可以改变它，添加top（），back（），pop（）等

尝试使用struct在C ++中创建循环缓冲区

1 个答案: