Question

嗨，我是Java脚本的新手，我想要以下情况的解决方案。我有一个多维坐标数组

var coordinateArr = [ [[45.56,45.57],[44.36,44.37]],
                      [[42.26,42.37],[42.46,42.57]],
                      [[41.56,41.57],[41.36,41.37],[41.26,41.27]] 
                    ];

我还有另一个多维数组，例如

var  anotherArr = [ [[41.56,41.57],[41.36,41.37],[41.26,41.27]], 
                     [[42.26,42.37],[42.46,42.57]]
                  ];

现在，我想像这样从coordinateArr中提取不匹配的值

var unmatchedArr= [[[45.56,45.57],[44.36,44.37]]];

我该怎么做？

Answer 1

Javascript通过引用进行数组比较，因此除非一组是同一对象，否则您不能简单地测试一组中的数组是否在另一组中。您需要测试每个值，或者将数组转换为按值进行比较的值，例如字符串。对于数组，可以使用JSON.stringify。如果您从Set中提取了anotherArr，则可以将filter与Set.has()

进行比较

var coordinateArr = [ [[45.56,45.57],[44.36,44.37]],
                      [[42.26,42.37],[42.46,42.57]],
                      [[41.56,41.57],[41.36,41.37],[41.26,41.27]] 
                    ];

var  anotherArr = [ [[41.56,41.57],[41.36,41.37],[41.26,41.27]], 
                     [[42.26,42.37],[42.46,42.57]]
                  ]; 

let keys = new Set(anotherArr.map(JSON.stringify))
let filtered = coordinateArr.filter(arr => !keys.has(JSON.stringify(arr)))

console.log(filtered)

Answer 2

尝试filter找出另一个数组中未include的数组元素：

var coordinateArr = [
  [
    [45.56, 45.57],
    [44.36, 44.37]
  ],
  [
    [42.26, 42.37],
    [42.46, 42.57]
  ],
  [
    [41.56, 41.57],
    [41.36, 41.37],
    [41.26, 41.27]
  ]
];

var anotherArr = [
  [
    [41.56, 41.57],
    [41.36, 41.37],
    [41.26, 41.27]
  ],
  [
    [42.26, 42.37],
    [42.46, 42.57]
  ]
];

var unmatchedArr = coordinateArr.filter(e => !anotherArr.includes(e));
console.log(unmatchedArr);

如何以最小的复杂性从JavaScript中的数组获取不匹配的数组值？

2 个答案: