如何获取每个id的数组的最小值

Question

我有一个练习，要求按银行ID列出包含薪资最低的客户的银行阵列。

const bills = [ 
   { Idclient: 2,  Idbank: 2, salary: 20000 }, 
   { Idclient: 3,  Idbank: 1, salary: 600 },
   { Idclient: 1,  Idbank: 3, salary: 3000 },
   { Idclient: 4,  Idbank: 1, salary: 2000 }, 
   { Idclient: 6,  Idbank: 2, salary: 300 },
   { Idclient: 5,  Idbank: 3, salary: 2500 },
   { Idclient: 7,  Idbank: 3, salary: 1000 },
];

function BankMinClient() {
  var min = bills.reduce(function(prev, current) {
    return (prev.Idclient > current.salary) ? prev : current
  })

  console.log(min)

  let map = bills.reduce(function(map, bill) {
    var bank_id = bill.Idbank;
    var balance = +bill.salary;
    map[bank_id] = (map[min]) + min

    return map

  }, {})

  return map
};
BankMinClient();

此函数返回整个数组的最低值，下面的函数列出了银行，但没有列出薪水较低的客户。仅显示：

 {1: "undefined [object Object]", 2: "undefined [object Object]", 3: 
"undefined [object Object]"}

任何想法如何解决？预先感谢。

所需的结果将是：

{1: 600, 2: 300, 3: 1000}

Answer 1

您确实需要使用reduce，但是如果有余额，则不想添加到现有余额中，而是 reassign 当前余额：

const bills = [ 
   { Idclient: 2,  Idbank: 2, salary: 20000 }, 
   { Idclient: 3,  Idbank: 1, salary: 600 },
   { Idclient: 1,  Idbank: 3, salary: 3000 },
   { Idclient: 4,  Idbank: 1, salary: 2000 }, 
   { Idclient: 6,  Idbank: 2, salary: 300 },
   { Idclient: 5,  Idbank: 3, salary: 2500 },
   { Idclient: 7,  Idbank: 3, salary: 1000 },
];
console.log(
  bills.reduce((a, { Idbank, salary }) => {
    const currentBalance = a[Idbank];
    if (currentBalance === undefined || salary < currentBalance) {
      a[Idbank] = salary;
    }
    return a;
  }, {})
);