Question

我正在创建一个机器人，只要计时器运行，它就可以执行鼠标单击操作，但不能超过此时间。就像leftmouseclick相比，它应该做387ms /发送垃圾邮件rightmouseclick并在每次两次rightmouseclick之间等待10ms

现在，我正在寻找一种方法来在循环中执行/发送rightmouseclick几毫秒的垃圾邮件（而不是间隔！）。

赞：

for(387ms)
{
   doSomething(); // doSomething() is rightmouseclick in my case
   wait(10ms);
}

doSomething（）在387ms的时间范围内尽可能地被执行，而wait（10ms）应该不会影响剩余时间，就像我认为使用Thread.Sleep(10)

Answer 1

我想这是更合适的选择，您可以调用下面的函数来获取所需的内容。

    public void TimerLoop(int ms)
    {
        var now = DateTime.Now; 
        while(DateTime.Now < now.AddMilliseconds(ms))
        {   
        //do your stuff here
        }
    }

Answer 2

这里有两种方法TimeLoop和TimeLoopAsync，它们将以特定的延迟在特定的时间量内循环操作。从中获得所需的东西，但它将满足您的需求。

using System;
using System.Threading;
using System.Threading.Tasks;

namespace ConsoleApp3
{
    class Program
    {
        static async Task Main(string[] args)
        {
            const int TotalTimeMS = 200;
            const int DelayMS = 10;
            TimeLoop(() =>
            {
                Console.WriteLine($"First {DateTime.Now.Ticks}");
            }, TotalTimeMS, DelayMS);

            await TimeLoopAsync(() =>
            {
                Console.WriteLine($"Second {DateTime.Now.Ticks}");
            }, TotalTimeMS, DelayMS);

            Console.WriteLine("Done");
            Console.ReadKey();
        }

        public static void TimeLoop(Action action, int totalTime, int delay)
        {
            var futureTime = DateTime.Now.AddMilliseconds(totalTime);
            while (futureTime > DateTime.Now)
            {
                action.Invoke();
                Thread.Sleep(delay);                
            }
        }

        public static async Task TimeLoopAsync(Action action, int totalTime, int delay)
        {
            var futureTime = DateTime.Now.AddMilliseconds(totalTime);
            while (futureTime > DateTime.Now)
            {
                action.Invoke();
                await Task.Delay(delay);
            }
        }
    }
}
//OUTPUTS
//First 636813466330097482
//First 636813466330207562
//First 636813466330317509
//First 636813466330427504
//First 636813466330537519
//First 636813466330647498
//First 636813466330757504
//First 636813466330867485
//First 636813466330977501
//First 636813466331087479
//First 636813466331197483
//First 636813466331307522
//First 636813466331417580
//First 636813466331527516
//First 636813466331637533
//First 636813466331747513
//Second 636813466331867481
//Second 636813466332197479
//Second 636813466332317508
//Second 636813466332427498
//Second 636813466332647472
//Second 636813466332757495
//Second 636813466332977526
//Second 636813466333087469
//Second 636813466333197468
//Second 636813466333417483
//Second 636813466333527481
//Second 636813466333757457
//Done

C＃循环x毫秒

2 个答案: