Question

我刚刚开始用Python编程。我目前正在尝试制作石头，纸，剪刀的游戏。要求用户选择一个代表三个选项之一的数字。而个人电脑会选择一个随机数。但是，我得到输入线的值错误。同一行在不同的上下文中可以正常工作（没有while循环），但是我看不到自己做错了什么。任何帮助将不胜感激。

我试图将字符串转换为浮点数，然后转换为整数。那没有用。此外，我已经将玩家输入数字y替换为随机数以测试其余代码。这工作得很好。

这是我收到的错误消息：

answerplayer = int (input('What is your choice? ')) #Error
ValueError: invalid literal for int() with base 10: "runfile

代码：

import random
win = False

while win == False:
    print ('Rock, Paper, Scissors. 0: Rock; 1: Scissors; 2: Paper')
    print ('Make your choice')
    answerplayer = int (input('What is your choice? ')) #Error
    answer = random.randrange (3)
    print (answerplayer)
    print (answer)
    if answer == 0 and answerplayer == 0 :
        print ('TIE')
    elif answer == 0 and answerplayer == 1 :
        print ('PC Win')
        win = True
    elif answer == 0 and answerplayer == 2 :
        print ('Player Win')
        win = True
    elif answer == 1 and answerplayer == 0 :
        print ('Player Win')
        win = True
    elif answer == 1 and answerplayer == 1 :
        print ('TIE')
    elif answer == 1 and answerplayer == 2 :
        print ('PC Win')
        win = True
    elif answer == 2 and answerplayer == 0 :
        print ('Player Win')
        win = True
    elif answer == 2 and answerplayer == 1 :
        print ('PC Win')
        win = True
    elif answer == 2 and answerplayer == 2 :
        print ('TIE')
    else:
        print ('Player Win')
        win = True

print ('done')

Answer 1

代码很好。用户输入必须是int()可以转换为整数的内容。

通行证：1 2 3.444
失败：sqfe zero

Answer 2

您可以解决：

while win == False:
    print ('Rock, Paper, Scissors. 0: Rock; 1: Scissors; 2: Paper')
    print ('Make your choice')
    answerplayer = input('What is your choice? ')
    if not answerplayer.isnumeric() :
        print ('No number')
        break
    answerplayer = int(answerplayer)
    answer = random.randrange (3)
    print (answerplayer)
    print (answer)

制作石头，纸张，剪刀游戏时出现值错误

2 个答案: