Question

例如：string ='AbcDEfGhIJK'

我想使用来获取列表： ['A'，'bc'，'DE'，'f'，'G'，'h'，'IJK']

我正在尝试这样做的逻辑，但到目前为止还算不上运气。

编辑：我不知道正则表达式，所以我只用了循环这就是我想出的，虽然它没有给出最后的“ IJK”

u_count = 0 
l_count = 0 
l_string = '' 
u_string = '' 
output = []

data = 'AbcDEfGhIJK'

for c in data:
 if(c.isupper()):
    if(l_count !=0):
        output.append(l_string)
        l_count = 0
        l_string = ''
    u_string += c
    u_count += 1

 if(c.islower()):
    if(u_count !=0):
        output.append(u_string)
        u_count = 0
        u_string = ''
    l_string +=c
    l_count += 1
print(output)

Answer 1

您可以使用itertools.groupby：

magz = [ 24.638505,  20.446914,  22.10271,   21.227533,  21.761152,  18.923867,
  24.054868,  23.92457,   21.515022,  21.835458,  21.204597,  21.848573,
  24.036382,  21.126777,  21.599414,  20.044833,  24.390594,  23.772577,
  19.608918,  22.676774,  23.6312,    24.12077,   21.22321,   20.350204,
  20.548614,  22.650914,  20.561528,  24.892959,  22.49959,   22.94469,
  24.346355,  23.934491,  22.448417,  20.535562,  20.785362,  25.131568,
  24.462043,  24.173652,  19.105512,  20.641586,  19.5268,    25.0747,    23.254556,
  24.460447,  24.37759,   22.708406,  20.765025,  17.27031,   22.723192,  22.4452,
  23.366233,  23.238118,  20.72437,   22.278445,  22.231206,  20.98687,
  20.341756,  22.968032,  22.504077,  21.277349,  19.163532,  22.44034,
  22.406581,  21.999019,  23.313155,  17.945062,  23.027715,  23.640596,
  20.60174,   20.124156,  22.39343,   23.786641,  25.201003,  25.227441,
  22.537135,  23.779794,  19.416995,  23.550315,  23.225908,  22.579364,
  21.69014,   20.50741,   22.543212,  21.640962,  20.425422,  23.793624,
  20.554366,  23.522594,  21.03864,   18.282573,  17.33285,   21.015233,
  21.611837,  24.00014,   22.741971,  24.416913,  24.053067,  24.314742,
  22.400808,  19.622712,  24.911735,  20.04981,   19.128503,  23.83536,
  21.864501,  25.037927,  24.449472,  24.200244,  24.492582,  22.378057,
  25.411336,  21.727248,  20.16391,   22.045026,  20.017703,  18.534318,
  21.995092,  21.434434,  21.825042,  22.78943,   19.006103,  22.398988,
  24.198657,  25.018417,  18.829948,  23.94818,   20.813966]

在这里，from itertools import groupby string = 'AbcDEfGhIJK' out = [''.join(group) for key, group in groupby(string, key=lambda c: c.islower())] print(out) # ['A', 'bc', 'DE', 'f', 'G', 'h', 'IJK']将为groupby提供相同输出的字符分组

Answer 2

您可以使用正则表达式：

import re

text = 'AbcDEfGhIJK'

result = re.split('([a-z]+)', text)
print(result)

输出

['A', 'bc', 'DE', 'f', 'G', 'h', 'IJK']

想法是将字符串拆分为小写字母'([a-z]+)'，但保持拆分模式。

Answer 3

str = 'AbcDEfGhIJK'
str=list(str)
for k,v in enumerate(str[:-1]):
    joined=''.join([str[k],str[k+1]])
    if joined.isupper() or joined.islower():
        str[k+1]=joined
        str[k]=''
str=[x for x in str if x!='']
print(str)

输出

['A', 'bc', 'DE', 'f', 'G', 'h', 'IJK']

获取字符串的子字符串

3 个答案: