PowerShell中的grep和sed等效项

Question

我正在尝试在PowerShell中执行以下语句

svn info filename | grep '^Last Changed Date:'| sed -e 's/^Last Changed Date: //'

我已经尝试过了：

svn info filename | Select-String '^Last Changed Date:'

我期望低于输出

Thursday, December 20, 2018 4:50:40 AM

Answer 1

使用-match和-replace operators：

(svn info filename) -match '^Last Changed Date:' -replace '^Last Changed Date: '

Answer 2

要删除开头的标签，您可以使用具有RegEx模式的捕获组。

svn info filename | Select-String '^Last Changed Date: (.*)$' | ForEach-Object{$_.Matches.Groups[1].Value)

或者在没有匹配的情况下采用Ansgars方法（并重复标签）

(svn info filename) -replace "(?sm).*?^Last Changed Date: (.*?)$.*","`$1"