Sed和人物

Question

我试图理解行代码。

这是什么意思？

   grep "^1  " file0 | grep -v MODEL | sed 's/./&E/86' | sed 's/./&  /8' | sed 's/./&  /20' > file1

Answer 1

# Add "E" after the 86th character
sed 's/./&E/86'

# Add "  " after the 8th character
sed 's/./&  /8'

# Add "  " after the 20th character
sed 's/./&  /20'

Answer 2

您可以将所有内容合并为一个grep表达式

，而不是在sed之前使用多个sed管道

sed '/^1  /{/MODEL/b;s/./&E/86;s/./&  /8;s/./&  /20}' file0 > file1