AttributeError:类型对象“ Image”没有属性“ open”

时间:2018-12-15 07:47:31

标签: python python-imaging-library

Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Python34\lib\tkinter\__init__.py", line 1482, in __call__
return self.func(*args)
File "C:\Users\TAO\Desktop\New\b.py", line 14, in imgs
img = Image.open("C:\\Users\\TAO\\Desktop\\New\\02.png")
AttributeError: type object 'Image' has no attribute 'open'

运行我的代码时出现此错误消息 我正在尝试为注册系统和身份证打印机进行编码 第一种形式是使用sqlite3数据库和tkinter GUI将数据导入数据库完成的。这种形式用于从数据库获取数据并写在照片数据上。制作身份证并打印。但是当我尝试使用Image.Open( ),它不起作用。

from PIL import *
import sqlite3
from tkinter import *

connection = sqlite3.connect("school.db")

tao = Tk()
tao.title("Mayurapada Central Collage")
tao.configure(bg = '#6699ff')
canvas = Canvas(tao,width = 600,height = 400,bg = '#6699ff')

def imgs():

    img = Image.open("C:\\Users\\TAO\\Desktop\\New\\02.png")
    img.show()
    str01 = "Image"
    font = ImageFont.truetype("arial.ttf",75)
    w,h = font.getsize(str01)
    print(str01)


button01 = Button(tao,text = "Preview",bd = 7,padx = 5,pady = 5,command = 
imgs).place(x = 50,y = 300)

canvas.pack()

tao.mainloop()

1 个答案:

答案 0 :(得分:1)

问题import *PIL.Imagetkinter.Image混淆。

import sqlite3
from tkinter import Tk, Button, Canvas
from PIL import Image, ImageFont

connection = sqlite3.connect("school.db")

tao = Tk()
tao.title("Mayurapada Central Collage")
tao.configure(bg = '#6699ff')
canvas = Canvas(tao,width = 600,height = 400,bg = '#6699ff')

def imgs():

    img = Image.open("C:\\Users\\TAO\\Desktop\\New\\02.png")
    img.show()
    str01 = "Image"
    font = ImageFont.truetype("arial.ttf",75)
    w,h = font.getsize(str01)
    print(str01)


button01 = Button(tao,text = "Preview",bd = 7,padx = 5,pady = 5,command = 
imgs).place(x = 50,y = 300)

canvas.pack()

tao.mainloop()