Question

我有一个带有一些坐标的字典，每个坐标为True或False。让我们说一个：

{(0, 0): False, (0, 1): False, (1, 0): True, (1, 1): False}

我想制作一个使用此字典的def，如果在坐标上为false，则打印带有空正方形的木板，如果在坐标上为true，则打印带有实心正方形的木板。到目前为止，我已经写了这个：

def printboard(board):
    sizer = int(get_size(board))
    for x in range(sizer):
        falseCount = 0
        trueCount = 0
        for y in range(sizer):
            if board[x,y] == False:
                falseCount += 1
            if board[x,y] == True:
                trueCount += 1
        print('⬛'*trueCount + '⬜'*falseCount)

但是当我编译它时，它不会打印出真正的正方形。有谁知道如何使这项工作？先感谢您！

Answer 1

您根本不需要计数，可以将print与end=""一起使用：

def printboard(board):
    mx = max(x for x,_ in board.keys() )
    my = max(y for _,y in board.keys() )

    for y in range(my+1):
        for x in range(mx+1): 
            print('⬛' if board[(x,y)] else '⬜', end= "") 
        print("") 

#           x  y
print('⬛' if board[(x,y)] else '⬜', end= "") False})

输出：

⬜⬛
⬜⬜

这将插入正确的换行符，并与非矩形输入配合使用。

Answer 2

你在这里

$ a2dismod php7.0
$ a2enmod php7.2
$ service apache2 reload

输出：

x = {
    (0, 0): False, (0, 1): False, 
    (1, 0): True,  (1, 1): False
}

# build a board and fills it with True (⬜)
def build_board(size):
    board = []
    for i in range(size):
        board += [[]]
        for j in range(size):
            board[i] += ['⬜']
    return board 

# fills False entries in the board from the dict (⬛)
def fill_board(data, board):
    for key, value in x.items():
        if value == False:
            board[key[0]][key[1]] = '⬛'
    return board   

# prints the board
def print_board(board):
    for i in range(len(board)):
        for j in range(len(board[i])):
            print(board[i][j], end = "")
        print()

## testing the functions
if __name__ == '__main__':
    board = build_board(2)
    board = fill_board(x, board)
    print_board(board)

如何用坐标打印板？

2 个答案: