在下面的列表中,我打算从每个列表中删除前三个元素:
x = [(0,1,2,3,5), (0,13,2,6,9), (0,7,8,42,3), (6,9,4,5,6)]
print(x)
预期的输出列表:
x = [(3,5), (6,9), (42,3), (5,6)]
我尝试过的事情:
#x.pop(0) //that would remove the whole (0,1,2,3,5)
#x = [1: ] //the would again eradicate (0,1,2,3,5)
答案 0 :(得分:0)
您可以使用:
y= [i[3:] for i in x ]
[(3, 5), (6, 9), (42, 3), (5, 6)]