Question

我正在使用elementtree / lists编辑标签，在从配置标签获取信息后，我想删除标签。我尝试在i.remove(j)下面这样做，如果我遍历列表列表，我可以看到确实删除了配置标记。但是当我写出文件时他们还在那里，为什么会这样，我该怎么删除它们？是我正在编辑子列表然后将不同的列表写入文件吗？

import xml.etree.ElementTree as ET
ET.register_namespace("", "http://clish.sourceforge.net/XMLSchema")
tree = ET.parse('ethernet.xml')
root = tree.getroot()

command= ""
pattern = ""
operation = ""
priority= ""

action_command = """/klas/klish-scripts/ifrange.py run_command --cmdrange "${interface_method} ${iface_num} ${range_separator} ${iface_num2}  ${range_separator2} ${interface_method2} ${iface_num3} ${range_separator3} ${iface_num4} ${range_separator4} ${interface_method3} ${iface_num5} ${range_separator5} ${iface_num6} ${range_separator6} ${interface_method4} ${iface_num7} ${range_separator7} ${iface_num8}" --command "%s" --klish_config "%s" --klish_action "%s" --priority "%s"
"""

commands = root.findall('{http://clish.sourceforge.net/XMLSchema}'
                        'VIEW/{http://clish.sourceforge.net/XMLSchema}COMMAND')
all1 = []

for command in commands:
    all1.append(list(command.iter()))

atr = ""
for i in all1:
    for j in i:
        if "COMMAND" in j.tag:
            if "name" in j.attrib:
                pattern = j.attrib['name']
                #print operation
        if "CONFIG" in j.tag:
            if "operation" in j.attrib:
                operation = j.attrib['operation']  
            else:
                operation = "set"  
            if "pattern" in j.attrib:
                pattern = j.attrib['pattern']                       
            if "priority" in j.attrib:
                priority = j.attrib['priority']
            else:
                if operation == "unset":
                    priority = ""
                else:
                    priority = "0x7f00"    

            atr = str(j.attrib)
            **i.remove(j)**

        if "ACTION" in j.tag: 
            if j.text:
                command = j.text.strip()
                j.text= action_command % (command, pattern, operation, priority)
            else:
                command = ""                        

cmd = ""
cmd += ifrange  


for o in all1:
    for y in o:
        print y
    **cmd += ET.tostring(o[0], encoding="utf-8", method="xml")**
cmd += end_tags


f = open('Z2.xml', 'w')
f.write(cmd)
f.close

编辑：解决方案，在我写入文件之前的文件末尾我将all1重置为[]。然后我循环遍历树，删除必要的元素。

all1 = []
for command in commands:
    for i in command:
         #print i
         if "CONFIG" in str(i):
             command.remove(i)
    all1.append(list(command.iter()))

Answer 1

您只是从列表中删除对元素的引用。您需要在父元素上调用.remove()。 ElementTree不保留父指针;仅给出一个CONFIG元素，您就无法返回其父级的VIEW元素。

这意味着您还需要保留对父级的引用。循环遍历VIEW元素，然后在嵌套循环中找到要删除的CONFIG元素，并且VIEW父级仍然可用，请调用.remove()删除子元素来自那个父母。

从elementtree / list中删除元素

1 个答案: