Question

我有一个表，其类型为varchar，varchar，日期和日期：

NAME | ID   | FROM       | THRU
Bob  | A123 | 10/30/2010 | 11/2/2010
Bob  | B567 | 10/30/2010 | 11/2/2010

我想添加一个服务日期（DOS）列，该列复制行并针对FROM和THRU日期之间（包括该日期）的每一天进行迭代。成品表应如下所示：

NAME | ID   | FROM       | THRU       | DOS
Bob  | A123 | 10/30/2010 | 11/02/2010 | 10/30/2010
Bob  | A123 | 10/30/2010 | 11/02/2010 | 10/31/2010
Bob  | A123 | 10/30/2010 | 11/02/2010 | 11/01/2010
Bob  | A123 | 10/30/2010 | 11/02/2010 | 11/02/2010
Bob  | B567 | 10/30/2010 | 11/02/2010 | 10/30/2010
Bob  | B567 | 10/30/2010 | 11/02/2010 | 10/31/2010
Bob  | B567 | 10/30/2010 | 11/02/2010 | 11/01/2010
Bob  | B567 | 10/30/2010 | 11/02/2010 | 11/02/2010

我看到了另一个使用cte但未保留原始日期值并添加DOS列的答案。如何在SQL Server中完成此操作？

Answer 1

我认为日历表不是这里的正确工具。由于您想要连续的日期，理货表似乎是个不错的选择。

首先让我们设置您的数据。

declare @Something table
(
    NAME varchar(10)
    , ID varchar(10)
    , DateFrom date
    , THRU date
)

insert @Something values
('Bob', 'A123', '20101030', '20101102')
, ('Bob', 'B567', '20101030', '20101102')

接下来，我们需要统计表。我在系统上保留一个视图，读取速度为零，读取速度很快。可以根据您的需要随意调整行数。

create View [dbo].[cteTally] as

WITH
    E1(N) AS (select 1 from (values (1),(1),(1),(1),(1),(1),(1),(1),(1),(1))dt(n)),
    E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
    E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
    cteTally(N) AS 
    (
        SELECT  ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
    )
select N from cteTally

现在，查询您的情况非常简单。

select s.Name
    , s.ID
    , s.DateFrom
    , s.THRU
    , DOS = DATEADD(day, t.N - 1, DateFrom)
from @Something s
join cteTally t on t.N <= datediff(day, DateFrom, THRU) + 1
order by s.Name
    , s.ID
    , t.N

Answer 2

听起来像您需要Calendar table。然后它变得像这样简单：

SELECT YT.Name,
       YT.ID,
       YT.[From],
       YT.Thru,
       CT.CalendarDate AS DOS
FROM dbo.YourTable YT
     JOIN dbo.CalendarTable CT ON CONVERT(date,YT.[From]) <= CT.CalendarDate
                              AND CONVERT(date,YT.Thru) >= CT.CalendarDate;

注意，我使用了自己的Calendar表，该链接没有相同的列（名称），但是，该链接提供了有关如何设计的所有信息。您只需要确保使用适合表的列名即可。

Answer 3

如果您没有日历表（强烈建议使用），则另一个选择是临时计价表

示例

Select A.* 
      ,DOS = B.D
 From  YourTable A
 Cross Apply (
                Select Top (DateDiff(DAY,[FROM],[THRU])+1) D=DateAdd(DAY,-1+Row_Number() Over (Order By (Select Null)),[FROM]) 
                  From  master..spt_values n1,master..spt_values n2
             ) B

返回

NAME    ID      FROM        THRU        DOS
Bob     A123    2010-10-30  2010-11-02  2010-10-30
Bob     A123    2010-10-30  2010-11-02  2010-10-31
Bob     A123    2010-10-30  2010-11-02  2010-11-01
Bob     A123    2010-10-30  2010-11-02  2010-11-02
Bob     B567    2010-10-30  2010-11-02  2010-10-30
Bob     B567    2010-10-30  2010-11-02  2010-10-31
Bob     B567    2010-10-30  2010-11-02  2010-11-01
Bob     B567    2010-10-30  2010-11-02  2010-11-02

Answer 4

对于这种事情，我经常使用递归CTE：

with cte as (
      select t.ame, t.id, t.from, t.thru, t.from as dos
      from t
      union all
      select cte.ame, cte.id, cte.from, cte.thur, dateadd(day, 1, dos)
      from cte
      where dos < t.thru
     )
select cte.*
from cte
option (maxrecursion 0);

Answer 5

您可以将服务日期创建为计算列。要增加日期，您可以尝试以下操作：

SELECT DATEADD(day, 1, '2017/08/25') AS DateAdd;

Answer 6

似乎CROSS APPLY会完成工作

CREATE TABLE T(
  [NAME] varchar(3), 
  [ID] varchar(4), 
  [FROM] datetime, 
  [THRU] datetime
);

INSERT INTO T
    ([NAME], [ID], [FROM], [THRU])
VALUES
    ('Bob', 'A123', '2001-10-30 00:00:00', '2001-11-02 00:00:00'),
    ('Bob', 'B567', '2001-10-30 00:00:00', '2001-11-02 00:00:00');

SELECT T.*,
       DATEADD(Day, TT.N, [FROM]) DOS
FROM T CROSS APPLY (VALUES (0), (1), (2), (3)) TT(N)

返回：

+------+------+---------------------+---------------------+---------------------+
| NAME |  ID  |        FROM         |        THRU         |         DOS         |
+------+------+---------------------+---------------------+---------------------+
| Bob  | A123 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 30/10/2001 00:00:00 |
| Bob  | A123 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 31/10/2001 00:00:00 |
| Bob  | A123 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 01/11/2001 00:00:00 |
| Bob  | A123 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 02/11/2001 00:00:00 |
| Bob  | B567 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 30/10/2001 00:00:00 |
| Bob  | B567 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 31/10/2001 00:00:00 |
| Bob  | B567 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 01/11/2001 00:00:00 |
| Bob  | B567 | 30/10/2001 00:00:00 | 02/11/2001 00:00:00 | 02/11/2001 00:00:0  |
+------+------+---------------------+---------------------+---------------------+

SQL Server-复制行并在两个日期值之间添加日期迭代器列

6 个答案: