我已经编写了这段代码,用自定义提供的字母替换字符串中的字符:
//Replaces characters in string with custom alphabet.
public static String getStringWithCustomAlphabet(String string, String customAlphabet){
String shiftedString = "";
//Loop through every character in @plainText
for (int i = 0; i < string.length(); i++) {
//Store current character of loop in @charToAdd
char charToAdd = string.charAt(i);
int index = getAlphabet().indexOf(charToAdd);
//If index is valid
if (index != -1) charToAdd = customAlphabet.charAt(index);
//Add the character to @cipherText
shiftedString += charToAdd;
}
return shiftedString;
}
public static String getAlphabet() {
return "abcdefghijklmnopqrstuvwxyz ";
}
此代码有效。但是,我希望不仅可以使用字符串字母,而且可以使用整数字母。因此,例如:
int[] numberArray {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26};
getStringWithCustomAlphabet("abcxyz", numberArray); //Should return 0,1,2,23,24,25
也许有一些方法可以简化此代码而不使用for循环?
答案 0 :(得分:0)
对于小写字母,请使用此:
String str = "abcdef";
char[] ch = str.toCharArray();
for (char c : ch) {
int temp = (int) c;
int temp_integer = 96; //for lower case
if (temp <= 122 & temp >= 97)
System.out.print(temp-temp_integer);
}
输出将为-:123456
大写:
String str = "DEFGHI";
char[] ch = str.toCharArray();
for (char c : ch) {
int temp = (int) c;
int temp_integer = 64; //for upper case
if (temp <= 90 & temp >= 65)
System.out.print(temp-temp_integer);
}
输出将为-:456789
答案 1 :(得分:0)
Strategy模式可以为您节省大量时间,并为您提供最大的灵活性。假设我们将AlphabetConverter
接口定义为:
@FunctionalInterface
interface AlphabetConverter {
String convert(char ch);
}
然后,将接受convertAlphabet
的{{1}}方法定义为:
AlphabetConverter
现在,您可以实现public String convertAlphabet(String actual, AlphabetConverter converter) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i < actual.length(); i++) {
sb.append(converter.convert(actual.charAt(i)));
}
return sb.ToString();
}
,一种实现用AlphabetConverter
字母代替,一种实现String
数组,甚至可以使用lambda函数。