Question

我正在编写一段python代码来替换一系列Alphabet。我知道该怎么做但不幸的是它只是替换了已经取代的那个。

lines=[]
replacements = {'a':'s','s':'d','d':'f','f':'g','g':'h','h':'j','j':'k','k':'l'}

with open("wrongString.txt") as infile:
    for line in infile:
        for src,target in replacements.iteritems():
            line = line.replace(src,target)
        lines.append(line)

with open("decode.txt","w") as outfile:
        for line in lines:              
            outfile.write(line)

wrongstring.txt：asdfghjkl

运行代码后，结果显示（encode.txt）：ggggkkkll

代码确实替换了＃34; a＆＃34;到＆＃34; s＆＃34;，并继续更换＆＃34; s＆＃34;成为＆＃34; d＆＃34;直到得到＆＃34; g＆＃34;以某种方式。我只是想取代＆＃34; a＆＃34;成为＆＃34; s＆＃34;然后停止更换它。

你能帮助我找到解决方案吗？

感谢您的回答！

Answer 1

使用 list comp ，这样您就不会覆盖任何替换的字符：

  line = "".join([replacements.get(ch, ch) for ch in line])

您也不需要存储所有行，只需按行编写行：

with open("wrongString.txt") as infile, open("decode.txt","w")  as outfile:
    outfile.writelines("".join([replacements.get(ch,ch) 
                                  for ch in line]) for  line in infile))

用python

1 个答案: