如何在subs查询mysql中添加查询限制

时间：2018-12-11 07:23:58

标签： mysql sql mariadb limit 

SELECT kodeagent
 , IFNULL((
   SELECT COUNT(1)
   FROM bsn_data
   WHERE bsn_data.periode LIKE '2018-12-%%'
   AND bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
   AND bsn_data.kodeagent IN(
       SELECT bsn_data.kodeagent
       FROM bsn_data
       WHERE bsn_data.periode LIKE '2018-12-%%'
       AND bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
       GROUP BY bsn_data.kodeagent ORDER BY COUNT(1) DESC LIMIT 1
       )
   ), 0) AS totps
FROM bsn_kode_agent
WHERE fungsi = 'sales agent'
ORDER BY totps DESC

获得结果

此版本的MariaDB尚不支持“ LIMIT＆IN / ALL / ANY / SOME子查询”

我该如何解决？我想在子查询中添加限制查询..谢谢..

4 个答案:

答案 0 :(得分：0)

没有什么可检查我的答案。请尝试此操作，将子查询包装在其他花药中，以提供tmp表别名（tmp_bsn_data）：

SELECT kodeagent
 , IFNULL((
   SELECT COUNT(1)
   FROM bsn_data
   WHERE bsn_data.periode LIKE '2018-12-%%'
   AND bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
   AND bsn_data.kodeagent IN( select tmp_bsn_data.kodeagent from (
       SELECT bsn_data.kodeagent
       FROM bsn_data
       WHERE bsn_data.periode LIKE '2018-12-%%'
       AND bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
       GROUP BY bsn_data.kodeagent ORDER BY COUNT(1) DESC LIMIT 1
       ) tmp_bsn_data
       )
   ), 0) AS totps
FROM bsn_kode_agent
WHERE fungsi = 'sales agent'
ORDER BY totps DESC

答案 1 :(得分：0)

我认为这会起作用：

SELECT ka.kodeagent
       (SELECT COUNT(1)
        FROM bsn_data d
        WHERE d.periode >= '2018-12-01' AND
              d.periode < '2019-01-01' AND
              d.kodeupline2 = ka.kodeagent AND
              d.kodeagent = (SELECT d2.kodeagent
                             FROM bsn_data d2
                                  d2.periode >= '2018-12-01' AND
                                  d2.periode < '2019-01-01' AND
                                  d2.kodeupline2 = ka.kodeagent
                             GROUP BY d2.kodeagent
                             ORDER BY COUNT(1) DESC
                             LIMIT 1
                            )
        ) AS totps
FROM bsn_kode_agent ka
WHERE ka.fungsi = 'sales agent'
ORDER BY totps DESC;

注意：

  • 不要在日期上使用字符串操作！使用正确的日期操作。
  • 使用表别名并限定表名称。
  • =可以使用limit，尽管in不能。
  • COUNT()不返回NULL，因此不需要进行NULL比较。

我仍然认为查询不会起作用，因为您有一个双重嵌套的相关子句。但这确实解决了您眼前的问题。

如果仍然无法解决问题，请提出另一个问题，提供示例数据，所需结果以及对您要实现的逻辑的解释。

答案 2 :(得分：0)

避免使用IN ( SELECT ... )

在这种情况下，将其变成JOIN应该很容易。

更改中间查询：

SELECT  COUNT(1)
    FROM  bsn_data
    WHERE  bsn_data.periode LIKE '2018-12-%%'
      AND  bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
      AND  bsn_data.kodeagent IN (
        SELECT  bsn_data.kodeagent
            FROM  bsn_data
            WHERE  bsn_data.periode LIKE '2018-12-%%'
              AND  bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
            GROUP BY  bsn_data.kodeagent
            ORDER BY  COUNT(1) DESC
            LIMIT  1 
                          )

到

SELECT  COUNT(1)
    FROM  
        ( SELECT  bsn_data.kodeagent
            FROM  bsn_data
            WHERE  bsn_data.periode >= '2018-12-01'
              AND  bsn_data.periode  < '2018-12-01' + INTERVAL 1 MONTH
              AND  bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
            GROUP BY  bsn_data.kodeagent
            ORDER BY  COUNT(1) DESC
            LIMIT  1 
        ) AS x
    JOIN  bsn_data  ON x.kodeagent = bsn_data.kodeagent
    WHERE  bsn_data.periode >= '2018-12-01'
      AND  bsn_data.periode  < '2018-12-01' + INTERVAL 1 MONTH
      AND  bsn_data.kodeupline2 = bsn_kode_agent.kodeagent

索引：

bsn_data:  INDEX(kodeupline2, periode, kodeagent)  -- in this order
bsn_data:  (kodeagent)  -- is this the PRIMARY KEY?

但是等等！不能简化为

SELECT  COUNT(1) AS ct
    FROM  bsn_data
    WHERE  bsn_data.periode >= '2018-12-01'
      AND  bsn_data.periode <  '2018-12-01' + INTERVAL 1 MONTH
      AND  bsn_data.kodeupline2 = bsn_kode_agent.kodeagent
    GROUP BY  bsn_data.kodeagent
    ORDER BY  COUNT(1) DESC
    LIMIT  1

答案 3 :(得分：0)

MariaDB提供了“窗口功能”，我相信可以利用此功能（也指前面的问题，似乎只需要“前3名”代理的计数即可）：

CREATE TABLE bsn_kode_agent(
   kodeagent VARCHAR(10) NOT NULL PRIMARY KEY
  ,fungsi    VARCHAR(40) NOT NULL
);

INSERT INTO bsn_kode_agent(kodeagent,fungsi) 
  VALUES
  ('a','sales agent')
, ('b','sales agent');

CREATE TABLE bsn_data(
   kodeagent   VARCHAR(1) NOT NULL
  ,kodeupline2 VARCHAR(2) NOT NULL
  ,periode     DATE  NOT NULL
);

INSERT INTO bsn_data(kodeagent,kodeupline2,periode) 
VALUES 
  ('a','b1','2018-12-01')
, ('a','b1','2018-12-01')
, ('a','b1','2018-12-01')
, ('a','c1','2018-12-01')
, ('a','c1','2018-12-01')
, ('a','c1','2018-12-01')
, ('a','d1','2018-12-01')
, ('a','d1','2018-12-01')
, ('a','e1','2018-12-01')
, ('a','f1','2018-12-01')
;

SELECT
    b.kodeagent
  , IFNULL( SUM( d.total ), 0 )  AS totps
FROM bsn_kode_agent AS b
LEFT JOIN (
        SELECT
            tableb.kodeupline2
          , tableb.kodeagent
          , tableb.total
          , ROW_NUMBER() OVER (PARTITION BY tableb.kodeagent
                                 ORDER BY tableb.total DESC) as rn
        FROM (
            SELECT
                bsn_data.kodeupline2
              , bsn_data.kodeagent
              , COUNT( 1 ) total
            FROM bsn_data
            WHERE  bsn_data.periode >= '2018-12-01'
              AND  bsn_data.periode <  '2018-12-01' + INTERVAL 1 MONTH
            GROUP BY
                bsn_data.kodeupline2
              , bsn_data.kodeagent
        ) AS tableb
    ) d ON d.kodeagent = b.kodeagent and d.rn <=3 
WHERE b.fungsi = 'sales agent'
group by
    b.kodeagent
ORDER BY
    totps DESC

kodeagent | totps
:-------- | ----:
a         |     8
b         |     0

以下：如果独立运行子查询结果。请注意，它是rn列，它允许仅对计数最高的代理进行后续过滤。

         SELECT
            tableb.kodeupline2
          , tableb.kodeagent
          , tableb.total
          , ROW_NUMBER() OVER (PARTITION BY tableb.kodeagent
                                 ORDER BY tableb.total DESC) as rn
        FROM (
            SELECT
                bsn_data.kodeupline2
              , bsn_data.kodeagent
              , COUNT( 1 ) total
            FROM bsn_data
            WHERE  bsn_data.periode >= '2018-12-01'
              AND  bsn_data.periode <  '2018-12-01' + INTERVAL 1 MONTH
            GROUP BY
                bsn_data.kodeupline2
              , bsn_data.kodeagent
        ) AS tableb

kodeupline2 | kodeagent | total | rn
:---------- | :-------- | ----: | -:
b1          | a         |     3 |  1
c1          | a         |     3 |  2
d1          | a         |     2 |  3
e1          | a         |     1 |  4
f1          | a         |     1 |  5

db <>提琴here

还请注意，有一些样本数据非常有用，但是，因为没有提供，我可能对此处看到的样本做出了不正确的假设-如果提供样本数据，总会更好问题。

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