Question

这是我的表测试，其值为：

Price
----------
300
600
900
1000
1800
2000

我想查询一下，当我搜索300时，我应该得到4条记录300,600,900,1000。

如果我搜索900，我可以获得600,900,1000,1800。即两个记录＆lt; = 900和两个记录＆gt; 900

这是我试过的查询：

SELECT * FROM table h where CONDITIONS 
 and  (price in (select price from table where price <=900) // I want to add   LIMIT 2 in this subquery
 or price in (select price from table where price >900)//LIMIT 2
)
order by FIELD(price ,900) DESC limit 5;

我在堆栈溢出上搜索了很多，但没有任何效果。请帮忙。

Answer 1

您可以尝试以下内容......

select * from ((select h.* from table_name h where amount <=300 order by amount desc limit 2)
union
(select h.* from table_name h where amount >300 order by amount limit 2)) 
derived_table order by FIELD(amount,300) desc;

Answer 2

MySQL在WHERE IN / EXSISTS / ANY / SOME子查询中不支持LIMIT，你可以使用UNION

(SELECT * /* this should be a columnlist */
 FROM tablename
 WHERE price < 900
 ORDER BY price LIMIT 2)

 UNION

(SELECT * /* this should be a columnlist */
 FROM tablename
 WHERE price >= 900
 ORDER BY price LIMIT 2)

每个选择的括号都是至关重要的。

See SQL Fiddle

Answer 3

使用union，因为此mysql版本不接受子查询中的限制

select * from table where price <=900 limit 2 union select * from table where price > 900 limit 2

MySQL Query在SubQuery中添加限制

3 个答案: