这是我的代码
from openpyxl import Workbook
from openpyxl import load_workbook
def get_data_list(filename, sheetname):
data = record = []
# load excel file, read only mode
wb = load_workbook(filename, read_only=True)
# select sheet
sheet = wb[sheetname]
# write into data
for row in sheet.rows:
for cell in row:
record.append(cell.value)
data.append(record)
record = []
return data
def write_data_list(data, filename, sheetname, no_header=False):
wb = Workbook()
sheet = wb.active
sheet.title = sheetname
# check header data
if no_header :
data.pop(0)
# insert data
for row in data:
sheet.append(row)
# save into file
wb.save(filename)
data = get_data_list('excel/sample.xlsx','Sheet1')
# print(type(data))
write_data_list(data, 'data.xlsx', 'data')
我运行以下代码并产生以下错误消息:
Traceback (most recent call last):
File "C:\Users\xxx\Projects\mergexl\rw.py", line 37, in <module>
write_data_list(data, 'data.xlsx', 'data')
File "C:\Users\xxx\Projects\mergexl\rw.py", line 31, in write_data_list
sheet.append(row)
File "C:\Users\xxx\.virtualenvs\mergexl-aotJkH4X\lib\site-packages\openpyxl\worksheet\worksheet.py", line 788, in append
self._invalid_row(iterable)
File "C:\Users\xxx\.virtualenvs\mergexl-aotJkH4X\lib\site-packages\openpyxl\worksheet\worksheet.py", line 872, in _invalid_row
type(iterable))
TypeError: Value must be a list, tuple, range or generator, or a dict. Supplied value is <class 'str'>
如您所见,此错误在第33行显示了一个问题,该问题“ sheet.append(row)” 一直在询问列表数据类型输入。但是,变量 data 已经是一个列表。我已经通过
检查了数据类型
print(type(data))
然后输出为类“列表” 但是错误消息不断告诉您 data 是类'str'
有什么解决办法吗?
答案 0 :(得分:1)
data = record = []
并没有按照您的想法做。
它将data
和record
的名称绑定到同一列表对象。
第一次运行以下循环时,data
和record
是相同的列表,并且在cell.value
被添加之前,第一行record
中的所有内容都已添加到该列表中。添加。
cell.value
不是列表类的实例。
for row in sheet.rows:
for cell in row:
record.append(cell.value)
data.append(record)
record = []
return data
您需要初始化数据并将其记录为单独的列表。
data = []
for row in sheet.rows:
record = []
for cell in row:
record.append(cell.value)
data.append(record)
return data