我正在尝试执行以下操作:通过查询获取ID列表,将其转换为以逗号分隔的字符串(即“ 1,2,3”),然后在辅助查询中使用它。尝试运行第二个查询时,出现语法错误:
“ lambda转换的目标类型必须是接口”
String query = "SELECT DISTINCT campaignId FROM `" + options.getEligibilityInputTable() + "` ";
Pipeline p = Pipeline.create(options);
p.apply("GetCampaignIds", BigQueryIO.readTableRows().withTemplateCompatibility().fromQuery(query).usingStandardSql())
.apply("TransformCampaignIds",
MapElements.into(TypeDescriptors.strings())
.via((TableRow row) -> (String)row.get("campaignId")))
.apply(Combine.globally(new StringToCsvCombineFn()))
.apply("GetAllCampaigns", campaignIds -> BigQueryIO.readTableRows().withTemplateCompatibility().fromQuery("SELECT id AS campaignId, dataQuery FROM `{projectid}.mysql_standard.campaigns` WHERE campaignId IN (" + campaignIds + ")").usingStandardSql())
....
如何将查询链接在一起?
答案 0 :(得分:1)
不幸的是,您不能使用现有来源执行此操作。您有两种选择:
第二个选项看起来像这样:
String query = "SELECT id AS campaignId, dataQuery \
FROM `{projectid}.mysql_standard.campaigns` \
WHERE campaignId IN ( \
SELECT DISTINCT campaignId \
FROM `" + options.getEligibilityInputTable()
+ "`)";
Pipeline p = Pipeline.create(options);
p.apply("GetAllCampaigns", BigQueryIO.readTableRows()
.withTemplateCompatibility()
.fromQuery(query)
.usingStandardSql());