我正在尝试配置服务器以管理至少3个客户端,但是当我这样做时,即使在连接第一个客户端之前,我仍然遇到内存不足错误。我该如何改善?在ThreadedEchoHandler()
中,我将接受客户端的请求,并接受包含服务器必须执行的所有操作的run方法。
public void initModel() throws IOException {
contenutoTextArea.append("Waiting for connections\n");
textarea.setText(contenutoTextArea.toString());
s = new ServerSocket(5000);
while (true) {
Runnable r = new ThreadedEchoHandler();
new Thread(r).start();
}
}
编辑:ThreadedEchoHandler的开始:
lass ThreadedEchoHandler implements Runnable {
private Socket incoming;
private String nomeAccount = "";
public void run() {
try {
incoming = s.accept();
} catch (IOException ex) {
System.out.println("Unable to accept requests");
}
}
答案 0 :(得分:1)
您应该在发生accept
循环的同一线程中执行while
,然后在建立新的接受连接之后,启动一个新线程:
while (true) {
Socket incoming = s.accept();
Runnable r = new ThreadedEchoHandler(incoming);
new Thread(r).start();
}
并修改ThreadEchoHandler
以从外部获取其Socket
:
class ThreadedEchoHandler implements Runnable {
final private Socket incoming;
private String nomeAccount = "";
ThreadedEchoHandler(Socket incoming) {
this.incoming = incoming;
}
public void run() {
// do stuff
}
}
您当然可以用各种方式来组织它,例如ThreadedEchoHandler
可以从构造函数中启动它的线程,甚至也可以执行accept
,但是同样,它必须在之前< / em>启动线程:
class ThreadedEchoHandler implements Runnable {
final private Socket incoming;
private String nomeAccount = "";
ThreadedEchoHandler(ServerSocket serv) throws IOException {
incoming = serv.accept();
new Thread(this).start();
}
public void run() {
// do stuff
}
}
然后循环可能是这样的:
while (true) new ThreadedEchoHandler(s);