PySide和PySide2之间的QKeySequence差异

Question

由于我当前正在将gui应用程序从Python 2.7.14 / PySide 1.2.4移植到Python 3.7.1 / PySide2 5.11.2，因此我在使用快捷方式机制时遇到了一些问题。更具体地说：

与PySide相比，
• QKeySequence实例化似乎在PySide2中返回不同/令人惊讶的结果。
• +枚举上的Qt.Key_*运算符似乎没有返回预期的结果。例如QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z)似乎无法正常工作。
• 使用字符串代码实例化QKeySequences时，它可以工作，例如QKeySequence("Shift+Ctrl+Z")似乎可以正常工作。
• 使用QKeySequence.StandardKey像QKeySequence(QKeySequence.Redo)这样的实例只会在PySide2中崩溃。

这些已知错误是吗？预期用法是否有所变化？我想念something in the docs吗？

Win7x64 / Python 3.7.1 / PySide2 5.11.2 （功能不正常/崩溃）

---

# -*- coding: utf-8 -*-
"""Test QKeySequence equality/matching in PySide2."""
from PySide2.QtCore import Qt
from PySide2.QtGui import QKeySequence

sequence_a = QKeySequence("Shift+Ctrl+Z")
sequence_b = QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z)

# string representation
print(sequence_a.toString())
print(sequence_b.toString())

print("-"*20)

# equality/matching
print(sequence_a.matches(sequence_b))
print(sequence_a == sequence_b)

print("-"*20)

# this causes a crash in PySide2 (Process finished with exit code -1073741819 (0xC0000005))
print(QKeySequence(QKeySequence.Redo))

# Ctrl+Shift+Z
# [
# --------------------
# PySide2.QtGui.QKeySequence.SequenceMatch.NoMatch
# False
# --------------------
# Process finished with exit code -1073741819 (0xC0000005)

Win7x64 / Python 2.7.14 / PySide 1.2.4 （正在运行）

---

# -*- coding: utf-8 -*-
"""Test QKeySequence equality/matching in PySide."""
from PySide.QtCore import Qt
from PySide.QtGui import QKeySequence

sequence_a = QKeySequence("Shift+Ctrl+Z")
sequence_b = QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z)

# string representation
print(sequence_a.toString())
print(sequence_b.toString())

print("-"*20)

# equality/matching
print(sequence_a.matches(sequence_b))
print(sequence_a == sequence_b)

print("-"*20)

# this works in PySide
print(QKeySequence(QKeySequence.Redo))

# Ctrl+Shift+Z
# Ctrl+Shift+Z
# --------------------
# PySide.QtGui.QKeySequence.SequenceMatch.ExactMatch
# True
# --------------------
# PySide.QtGui.QKeySequence(67108953, 0, 0, 0)

Answer 1

目前，出现了两种可能的解决方法：

---

• 错误：：QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z).toString()-> "["
• 通过强制优先级修复： QKeySequence(Qt.SHIFT + (Qt.CTRL + Qt.Key_Z)).toString()-> "Ctrl+Shift+Z"
• 按位或运算符固定： QKeySequence(Qt.ShiftModifier | Qt.CTRL | Qt.Key_Z).toString()-> "Ctrl+Shift+Z"

尽管它们似乎可以解决眼前的直接问题，但由于各种原因，我认为它们并不是那么出色。一般问题仍可能符合PySide2错误！？