作为输入,您有2个表: -一个带有user_id,signup_timestamp的 -第二个用户名为user_id,order_timestamp
我的理解:
答案 0 :(得分:0)
嗯,实际上很难解决这个问题,因为您不能使用简单的表格有效地显示答案。但是我很确定这将符合您的意愿。该代码可能有一些错误,因为我在打电话。
SELECT * FROM
(SELECT DATEPART(week, t1.signup_timestamp) AS week, count(signup) AS purchases
FROM table1)
t1
FULL OUTER JOIN
(SELECT
DATEPART(week, t1.order_timestamp) AS week, count(signup) AS orders
FROM table2)
t2
on t1.week = t2.week