如何获取DB2中同一列的最短日期

Question

Need to get order qty of the minimum ADATE

我使用下面的查询并获得12条记录。现在我想选择最小ADATE的orderqty，即06-NOV-2018（2018-11-06）。 对于每个客户（将获得多个记录），我需要获取最小ADATE列的Order_Qty。

select
   Customer ,
   OrderID ,
   LocationID ,   
   Order_Qty,Sent_date ,ADATE
   from
   (
      select
      OrderID ,
      LocationID ,
      Sent_date ,
      Order_Qty ,
      Customer ,
      TimeStampA
      from ARC_TBL
   )
   obn
   inner join
   (
      select
      ADATE ,TimeStampA
      from trackTBL snt
   )snt
   on obn.TimeStampA = snt.TimeStampA
    where Customer='ABC' and OrderID='XYZ100' and Sent_date='2018-11-18' and LocationID='250';

Answer 1

SELECT QTY, ADATE
  FROM table
 ORDER BY ADATE 
 FETCH FIRST 1 ROW ONLY

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