在列中显示值的最小数目

Question

我使用了一条select语句来获取俱乐部名单的数量：

SELECT club,COUNT(club) as mycount FROM member GROUP BY club


   CLUB            COUNT      
--------------- -----------

UCLA  Club                 5
George Club                11

我需要显示计数表的最小数量：

    CLUB            COUNT
--------------- -----------
UCLA Club                  5

我使用了此语句，但它只显示了最小数目，因为我需要表格看起来像上面的那一列一样。如何获得俱乐部名称：

选择MIN（mycount）作为COUNT FROM（选择俱乐部，按俱乐部的COUNT（club）mycount FROM成员组）

我尝试做：

SELECT俱乐部，MIN（mycount）为Count FROM（SELECT俱乐部，COUNT（club）mycount FROM yrb_member group by俱乐部）

但是当我在选择之后放俱乐部时，这给了我一个错误

Answer 1

使用order by和fetch first：

SELECT club, COUNT(club) as mycount
FROM member
GROUP BY club
ORDER BY COUNT(club)
FETCH FIRST 1 ROWS WITH TIES;

注意：有关系时，此返回多行。

编辑：

如果您需要处理领带，请使用RANK()：

SELECT club, mycount
FROM (SELECT club, COUNT(club) as mycount,
             RANK() OVER (ORDER BY COUNT(club) DESC) as seqnum
      FROM member
      GROUP BY club
     ) m
WHERE seqnum = 1;

Answer 2

我的回答更长了一点，但让我难以置信。

SELECT cl.club, cnt.mincnt FROM
    (SELECT club, COUNT(*) cnt FROM member GROUP BY club) cl,
    (SELECT MIN(cnt) mincnt FROM (SELECT club, COUNT(*) cnt FROM member GROUP BY club)) cnt
WHERE cl.cnt = cnt.mincnt;