我正在构建我的第一个Flutter应用程序,并且遇到了一些异步问题。
当我的应用程序执行时,我希望它请求权限并等待它们被授予。我的main()函数如下所示:
RED=(255,0,0)
BLACK=(0,0,0)
WHITE =(255,255,255)
GREEN = (0,255,0)
player_health = 10
enemy_health = 10
collision_counter = 0
attack_counter = 0
attack = False
import pygame
#Creating screen and sprites
all_sprites_list = pygame.sprite.Group()
all_enemies_list = pygame.sprite.Group()
pygame.init()
screen = pygame.display.set_mode((1,1))
class Sprites(pygame.sprite.Sprite):
def __init__(self,x,y,img):
super().__init__()
#Colour and position
#Set the background colour and set the image to be transparent
self.image = pygame.Surface([x, y])
self.image.fill(WHITE)
self.image.set_colorkey(WHITE)
#Or using an image
self.image = pygame.image.load(img).convert_alpha()
#Fetch a rectangle that is the same size
self.rect = self.image.get_rect()
self.mask = pygame.mask.from_surface(self.image)
def AI(self,charX):
#If the player is on the left
if self.rect.x < charX:
self.rect.x += 1
#On right
if self.rect.x > charX:
self.rect.x -= 1
def update(self,charX):
self.AI(charX)
img = "BadCrab.png"
#Creating the first AI sprite with width,height,colour and x,y position
AI1 = Sprites(30,20,img)
AI1.rect.x = 0
AI1.rect.y = 150
#Adding to to the necessary groups
all_enemies_list.add(AI1)
#Creating the character sprite with width,height,colour and x,y position
char = Sprites(30,20,"Crab.fw.png")
char.rect.x = 150
char.rect.y = 150
#Adding to to the necessary group
all_sprites_list.add(char)
screen = pygame.display.set_mode((800,400))
clock = pygame.time.Clock()
counter = 0
while True:
pygame.event.pump()
screen.fill(BLACK)
clock.tick(60)
pygame.event.pump()
keys = []
#Getting the keys which are pressed down
for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
keys.append(event)
#Converting the array to a string so it can be searched
keys=str(keys)
#Using the keys numbern value to determine if it has been pressed
#Left arrow = 276
if "276" in keys:
char.rect.x -= 40
#Right arrow = 275
elif "275" in keys:
char.rect.x += 40
counter += 1
#Space = 32
if "32" in keys:
counter = 0
#Removing orignal sprite and then changing it to the attack sprite
all_sprites_list.remove(char)
char = Sprites(30,20,"Crab_attack.fw.png")
char.rect.y = 150
char.rect.x = charX
all_sprites_list.add(char)
attack = True
#Allwoing the attack sprite to be drawn before replaced by original sprite
if counter == 12:
all_sprites_list.remove(char)
char = Sprites(30,20,"Crab.fw.png")
char.rect.y = 150
char.rect.x = charX
all_sprites_list.add(char)
counter = 0
attack = False
charX = char.rect.x
all_enemies_list.update(char.rect.x)
all_enemies_list.draw(screen)
all_sprites_list.draw(screen)
pygame.display.flip()
#Checking for collisions
collisions = pygame.sprite.groupcollide(all_sprites_list, all_enemies_list,False,False)
print(str(collisions))
Permission Manager类的get_permissions()函数使用Flutter Simple Permissions软件包检查并询问权限。
import 'permission_manager.dart' as Perm_Manager;
void main() async
{
//Ensure valid permissions
Perm_Manager.Permission_Manager pm = Perm_Manager.Permission_Manager();
var res = await pm.get_permissions();
print(res);
return runApp(MyApp());
}
当我运行应用程序时,它不会等待功能按预期完成,并会在更新Future之前打印“ res”的值。
import 'package:simple_permissions/simple_permissions.dart';
import 'dart:io' as IO;
import 'dart:async';
class Permission_Manager {
/* Get user permissions */
Future<bool> get_permissions() async
{
//Android handler
if (IO.Platform.isAndroid)
{
//Check for read permissions
SimplePermissions.checkPermission(Permission.ReadExternalStorage).then((result)
{
//If granted
if (result)
return true;
//Otherwise request them
else
{
SimplePermissions.requestPermission(Permission.ReadExternalStorage)
.then((result)
{
// Determine if they were granted
if (result == PermissionStatus.authorized)
return true;
else
IO.exit(0); //TODO - display a message
});
}
});
}
else
return true;
}
}
Future在函数中途返回一个值!有人知道我在做什么错吗?
答案 0 :(得分:3)
要等待某件事,您将来必须调用await
而不是.then
final result = await future;
// do something
代替
future.then((result) {
// do something
});
如果您真的要使用.then
,则可以等待生成的将来:
await future.then((result) {
// do something
});
只要确保在使用嵌套异步调用时,在每个异步调用上使用async关键字即可:
await future.then((result) async{
// do something
await future.then((result_2) {
// do something else
});
});
答案 1 :(得分:-2)
使其正常工作。该问题似乎可以通过使用Completer解决:
import 'package:simple_permissions/simple_permissions.dart';
import 'dart:io' as IO;
import 'dart:async';
class Permission_Manager {
/* Get user permissions */
final Completer c = new Completer();
Future get_permissions() async
{
//Android handler
if (IO.Platform.isAndroid)
{
//Check for read permissions
SimplePermissions.checkPermission(Permission.ReadExternalStorage).then((result)
{
//If granted
if (result)
{
c.complete(true);
}
//Otherwise request them
else
{
SimplePermissions.requestPermission(Permission.ReadExternalStorage).then((result)
{
// Determine if they were granted
if (result == PermissionStatus.authorized)
{
c.complete(true);
}
else
{
IO.exit(0); //TODO - display a message
}
});
}
});
}
else
{
c.complete(true);
}
return c.future;
}
}