熊猫：以10分钟为间隔绘制时间直方图

Question

我有一个这种格式的数据框：

    DATE        NAME        ARRIVAL TIME
275 2018-07-05  Adam    19:33:51.579885
276 2018-07-05  Bill    19:38:57.578135
277 2018-07-05  Cindy   19:40:24.704381
278 2018-07-05  Don     19:34:29.689414
279 2018-07-05  Eric    19:33:54.173609

我想绘制固定桶中到达时间的直方图，例如每10分钟。

利用其他答案中的跟踪代码，我设法产生了以下直方图：

df['ARRIVAL TIME'] = pd.to_datetime(df['ARRIVAL TIME'])
plt.hist([t.hour + t.minute/60. for t in df['ARRIVAL TIME']], bins = 8)

那接近我想要的。但是，我希望将垃圾箱设置为“ 7:30”，“ 7:40”等。

Answer 1

如果您只想手动更改默认刻度标签（例如，this answer），则应该可以执行以下操作（在运行已经完成的命令之后）：

plt.draw()      # do this so that the labels are generated
ax = plt.gca()  # get the figure axes
xticks = ax.get_xticklabels()  # get the current x-tick labels
newlabels = []
for label in xticks:
    h, m = divmod(float(label.get_text())%12, 1)  # get hours and minutes (in 12 hour clock)
    newlabels.append('{0:02d}:{1:02d}'.format(int(h), int(m*60)))  # create the new label

ax.set_xticklabels(newlabels)  # set the new labels

但是，如果要专门设置直方图框的边缘间隔为10分钟，则可以执行以下操作：

import numpy as np

# get a list of the times
times = [t.hour + t.minute/60. for t in df['ARRIVAL TIME']]

# set the time interval required (in minutes)
tinterval = 10.

# find the lower and upper bin edges (on an integer number of 10 mins past the hour)
lowbin = np.min(times) - np.fmod(np.min(times)-np.floor(np.min(times)), tinterval/60.)
highbin = np.max(times) - np.fmod(np.max(times)-np.ceil(np.max(times)), tinterval/60.)
bins = np.arange(lowbin, highbin, tinterval/60.)  # set the bin edges

# create the histogram
plt.hist(times, bins=bins)
ax = plt.gca()  # get the current plot axes
ax.set_xticks(bins)  # set the position of the ticks to the histogram bin edges

# create new labels in hh:mm format (in twelve hour clock)
newlabels = []
for edge in bins:
    h, m = divmod(edge%12, 1)  # get hours and minutes (in 12 hour clock)
    newlabels.append('{0:01d}:{1:02d}'.format(int(h), int(m*60)))  # create the new label

ax.set_xticklabels(newlabels)  # set the new labels