Question

decimal = int(input("Enter the Decimal value :"))

def d_b(decimal,binary):
    # function to convert decimal to binary
    binary = binary + str(decimal % 2)
    if decimal > 1:
        d_b(decimal//2,binary)
    else :
        print (binary)
        return (binary)

print ("Decimal to Binary : ", d_b(decimal,binary = ''))

输入34的输出：

010001

十进制转换为二进制：无

该函数会打印答案，但不会返回答案，然后开始返回到函数，并开始从字符串中逐个删除字符，最后不返回任何字符，而是返回二进制字符串。

正确的代码：

decimal = int(input("Enter the Decimal value :"))

def d_b(decimal,binary):
    # function to convert decimal to binary
    if decimal > 0:
        binary = d_b(int(decimal)//2,binary)
        binary = binary + str(decimal % 2)
    return (binary)

print ("Decimal to Binary :",d_b(decimal,binary = ''))

Answer 1

尝试一下，不客气：

def d_b(decimal,binary):
    # function to convert decimal to binary
    binary = binary + str(decimal % 2)
    if decimal > 1:
        binary = d_b(int(decimal/2), binary) # <-- this is the line you should change
    return binary

或什至更短的三元运算符：

return decimal > 1 ? d_b(int(decimal/2), binary): binary

十进制到二进制代码的递归函数混淆？

1 个答案: