Question

我知道如何找到最大的数字，但不知道如何打印该行？ ................................................... ................................................... ..........

#include <stdio.h>
#include <stdlib.h>
#define MAX 100
int main()
{
    int i,j,n, max_i, max_j;
    printf("Input size of a matrix:");
    scanf("%d", &n);
    int mat[n][n];


    printf("Input numbers in matrix:");
    for (i=0;i<n;i++){
        for (j=0;j<n;j++){
            scanf("%d", &mat[i][j]);
        }
    }
    max_i=0;
    max_j=0;
    for (i=0;i<n;i++){
        for (j=0;j<n;j++){
            if(mat[max_i][max_j]>mat[i][j]){
                mat[i][j]=mat[max_i][max_j];
            }
        }
    }
    printf("Largest number is %d, print of his whole row is %d", mat[max_i][max_j], mat[i][0] ); // I think here is a problem, but who knows
    return 0;
}

Answer 1

您所做的几乎是正确的，也就是说，您实际上是在寻找最大数字所在的索引（而不只是获取最大数字的值）。

更新max-indices只是一个错误，因为...

if(mat[max_i][max_j]>mat[i][j]){
         mat[i][j]=mat[max_i][max_j];  // alters the contents of the matrix
}

更改矩阵的内容，而不是更新搜索的索引。

写

if(mat[max_i][max_j] < mat[i][j]){
         max_i = i;
         max_j = j;
}

，最后应该有最大值所在的索引：

printf("maximum value is %d and is located at %d/%d\",mat[max_i][max_j],max_i,max_j);

Answer 2

如果google翻译正确，并且我理解您想要什么-因此您需要一张一张地打印它，或者在循环之前收集它：

printf("Najveci broj je %d, a ispis cijelog retka je ", mat[max_i][max_j]);
for(j = 0; j < n; j++) {
    printf("%d ", mat[max_i][j]);
}

Answer 3

创建一个变量以存储最大数目和该数目的行。

#include <stdio.h>
#include <stdlib.h>
#define MAX 100
int main()
{
int i,j,n, max_number, max_number_row;
printf("Ucitajte velicinu matrice:");
scanf("%d", &n);
int mat[n][n];


printf("Ucitajte brojeve u matricu:");
for (i=0;i<n;i++){
    for (j=0;j<n;j++){
        scanf("%d", &mat[i][j]);
    }
}

max_number = mat[0][0];
for (i=0;i<n;i++){
    for (j=0;j<n;j++){
            if(mat[i][j] > max_number){
                max_number = mat[i][j];
                max_number_row = i;
            }
    }
}
printf("Najveci broj je %d, a ispis cijelog retka je %d", max_number, max_number_row ); 
return 0;
}

编辑1：

就像另一个答案中提到的myxaxa一样，如果要打印行的每个数字，都需要遍历max_number_row。

#include <stdio.h>
#include <stdlib.h>
#define MAX 100
int main()
{
int i,j,n, max_number, max_number_row;
printf("Ucitajte velicinu matrice:");
scanf("%d", &n);
int mat[n][n];


printf("Ucitajte brojeve u matricu:");
for (i=0;i<n;i++){
    for (j=0;j<n;j++){
        scanf("%d", &mat[i][j]);
    }
}

max_number = mat[0][0];
for (i=0;i<n;i++){
    for (j=0;j<n;j++){
            if(mat[i][j] > max_number){
                max_number = mat[i][j];
                max_number_row = i;
            }
    }
}
printf("Najveci broj je %d, a ispis cijelog retka je ", max_number); 
for(j = 0; j < n; j++) {
    printf("%d ", mat[max_number_row][j]);
} 
return 0;
}

如何在二维数组中找到最大数字的行上打印？

3 个答案: