Question

我的代码有以下输出

代码：text = soup.get_text()

输出：

Article Title

    Some text: Text blurb.

More blurb.

Even more blurb. 

Some more blurb. 





Second Article Title

Some text: Text blurb.

More blurb.

Even more blurb. 

Some more blurb.

接下来，当我执行test = text.splitlines()时，输出更改为

u'Article Title', u'', u'Some text',u'Text blurb',u'More blurb',u'Even more blurb',u'Some more blurb',, u'', u'', u'', u'', u'',u'Second Article Title', u'', u'Some text:',u'Text blurb',u'More blurb',u'Even more blurb',u'Some more blurb',, u'', u'', u'', u'', u'',

我想使用u'', u'', u'', u'', u''分割字符串，以便随后分别解析各行。我本来希望使用这些标签，但是它们的结构使其难以使用。

如何执行拆分？我尝试过：

result = [list(g) for k,g in groupby(test,lambda x:x=="u''") if not k]
print result

和

for item in test:
    arr = re.split("u'', u'', u'', u'', u''",item, flags=re.UNICODE)
    print arr

但是他们没有给我想要的输出。

Answer 1

如果您查看文字，则希望通过重复的换行符samp1 = [1, 3, 5, 7, 9, 11, 13] samp2 = [2, 4, 6, 8, 10, 12, 14] def prac(ncoll, samp1, samp2): m = 4*pc.u sp1 = [] sp2 = [] for i in range(ncoll): a = random.choices(samp1) b = random.choices(samp2) sp1.append(a) sp2.append(b) np.concatenate(sp1) np.concatenate(sp2) en1 = 0.5*m*np.square(sp1) en2 = 0.5*m*np.square(sp2) diff = (en1-en2) absdiff = np.abs(diff) halfen = 0.5*absdiff if diff[i] >= 0: finalen1 = en1[i] - halfen finalen2 = en2[i] + halfen else: finalen1 = en1[i] + halfen finalen2 = en2[i] - halfen finalsp1 = np.sqrt((2*finalen1)/m) finalsp2 = np.sqrt((2*finalen2)/m) return finalsp1, finalsp2 print(prac(2, samp1, samp2))来分隔

\n

然后，您可以仅使用text >> 'Article Title\n\n Some text: Text blurb.\n\nMore blurb.\n\nEven more blurb. \n\nSome more blurb. \n\n\n\n\n\nSecond Article Title\n\nSome text: Text blurb.\n\nMore blurb.\n\nEven more blurb. \n\nSome more blurb. '的定义参数，如果不添加参数，Python只会按空格分隔。第一次拆分后，您可以按text.split('\n\n\n\n\n')拆分其他元素。

\n\n

在列表中从BeautifulSoup输出拆分字符串

1 个答案: