Question

我对此Python脚本有疑问。我正在尝试从具有家庭字符串的列表中传递值。我已经附上了剧本。在此命令page = requests.get("https://www.google.dz/search?q=lista[url]")中，我必须将要查找的内容放在search?q=之后。我想搜索多个关键字，所以我做了一个清单。我不怎么在该命令中传递列表中的值...

import requests
import re
from bs4 import BeautifulSoup

lista = []
lista.append("Samsung S9")
lista.append("Samsung S8")
lista.append("Samsung Note 9")

list_scrape = []

for url in lista:
    page = requests.get("https://www.google.dz/search?q=lista[url]")
    soup = BeautifulSoup(page.content)
    links = soup.findAll("a")
    for link in  soup.find_all("a",href=re.compile("(?<=/url\?q=) 
    (htt.*://.*)")):
        list_scrape.append(re.split(":(?=http)",link["href"].replace("/url?q=","")))

print(list_scrape)

谢谢！

Answer 1

使用format

for url in lista:
    page = requests.get("https://www.google.dz/search?q={}".format(url))

或

page = requests.get("https://www.google.dz/search?q=%s" % url)

Answer 2

尝试一下。

for url in lista:
    page = requests.get("https://www.google.dz/search?q="+url)

或

page = requests.get("https://www.google.dz/search?q={}".format(url))

如何从URL字符串中的列表传递值

2 个答案: