Question

我有大约1000记录的数据值，我想根据类别在同一模板文件中显示该数据的子集。我在寻找真正可行的解决方案时遇到了麻烦。下面是我的目的，但我很确定有一种更有效的方法来实现此目的。

查看

def man_org_list(request):
    manufacturers = Organization.objects.filter(member__member_flag=1, member__member_type='Manufacturer').order_by('id')
    suppliers = Organization.objects.filter(member__member_flag=1, member__member_type='Supplier').order_by('id')
    distributor = Organization.objects.filter(member__member_flag=1, member__member_type='distributor').order_by('id')
    return render(request, 'profiles/man_dash.html', {'man': manufacturers, 'sup': suppliers, 'dist': distributor})

urls.py

urlpatterns = [
    url(r'^$', views.org_list, name='org_list'),
    url(r'^(?P<id>\d+)/$', views.org_details, name='org_details'),
    url(r'^man_dash/', views.man_org_list, name='man_org_list')
]

我要根据类别更改的部分代码：

{% if request.get_full_path == '/profiles/man_dash/manufacturers/' %}
  {% for org in man %}
      <tr>
        <th scope="row">{{ org.id }}</th>
        <td>{{ org.org_name }}</td>
        <td>{{ org.org_type }}</td>
        {% for member in org.member.all %}
        <td>{{ member.member_flag }}</td>
        {% endfor %}
        {% for c_score in org.c_score.all %}
        <td>{{ c_score.completeness_score }}%</td>
        {% endfor %}
        <td><a href="{% url 'org_details' org.id %}" target="_blank">View</a></td>
      </tr>
  {% endfor %}
{% endif %}

您可以在代码段中看到，我正在使用request.get_full_path来匹配URL路径以显示数据。但是，使用这种方法，我将不得不复制同一代码块3次而只更改一页，这使我相信这不是实现此目的的理想方法。

是否有更好的方法可以通过视图或url.py？

Answer 1

我；我不确定那是否是您所需要的，但请尝试。

首先，您的网址似乎无法正确匹配：

让我们添加将从网址中捕获的member_type参数

urlpatterns = [
    url(r'^$', views.org_list, name='org_list'),
    url(r'^(?P\d+)/$', views.org_details, name='org_details'),
    url(r'^man_dash/<str:member_type>/', views.man_org_list, name='man_org_list')
]

现在将kwarg添加到视图中：

def man_org_list(request, member_type=None):
    member_type_map = {
        'manufacturers': 'Manufacturer',
        'suppliers': 'Supplier',
        'distributors': 'distributor'
    }

    member_type = member_type_map.get(member_type, None)
    if member_type is None:
        raise Http404
    queryset = Organization.objects.filter(member__member_flag=1, member__member_type=member_type).order_by('id')
    return render(request, 'profiles/man_dash.html', {'object_list': queryset})

现在您的模板仅需要遍历对象列表

{% for org in object_list %}
      <tr>
        <th scope="row">{{ org.id }}</th>
        <td>{{ org.org_name }}</td>
        <td>{{ org.org_type }}</td>
        {% for member in org.member.all %}
        <td>{{ member.member_flag }}</td>
        {% endfor %}
        {% for c_score in org.c_score.all %}
        <td>{{ c_score.completeness_score }}%</td>
        {% endfor %}
        <td><a href="{% url 'org_details' org.id %}" target="_blank">View</a></td>
      </tr>
  {% endfor %}

Django：使用if elif在基于URL的视图中显示不同的数据

1 个答案: