Question

它说第10行我有错误，不知道为什么

继承我的代码：

<?php
$os1= (isset($_GET['number']) && ($_GET['number'] == 'one' || $_GET['number'] == 'two' || $_GET['number'] == 'three'));
$os2= (isset($_GET['number']) && ($_GET['number'] == 'four' || $_GET['number'] == 'five' || $_GET['number'] == 'six'));


if ($os1)
 {
$title = "Windows 8";
$title2 = "User"
 }

else ($os2)
 {
$title = "OSX Yosimite";
$title2 = "User"
 }


 echo $title1;
 echo $title2;
 ?>

Answer 1

您在两个地方缺少;：

if ($os1)
 {
$title = "Windows 8";
$title2 = "User"; // add ; here
 }

else ($os2)
 {
$title = "OSX Yosimite";
$title2 = "User"; // add ; here
 }

更改

else ($os2)

到

else if ($os2)

以上逻辑适合作为解决方案，就好像我们只使用else而不是else if一样，没有使用变量$os2。

再次

更改

echo $title1;

到

echo $title;

Answer 2

失踪;排在第10位; 15

   <?php
    $os1= (isset($_GET['number']) && ($_GET['number'] == 'one' || $_GET['number'] == 'two' || $_GET['number'] == 'three'));
    $os2= (isset($_GET['number']) && ($_GET['number'] == 'four' || $_GET['number'] == 'five' || $_GET['number'] == 'six'));


    if ($os1)
     {
    $title = "Windows 8";
    $title2 = "User";
     }

    else ($os2)
     {
    $title = "OSX Yosimite";
    $title2 = "User";
     }


     echo $title1;
     echo 

$title2;
     ?>

Answer 3

变量＆＃34; $ title1＆＃34;未定义任何位置（或）在打印前不指定任何值。

echo $ title1;

Answer 4

您在第9行和第15行的末尾错过了分号（;）。请检查。

每一行都应以PHP中的分号结尾，否则它会给我们带来错误:-D

Answer 5

   <?php
   $arr1=array("one","two","three");
   $arr2= array("four","five","six");
   if(isset($_GET['number']) && in_array($_GET['number'],$arr1))
   {
       $title = "Windows 8";
       $title2 = "User";
   }
   elseif (if(isset($_GET['number']) && in_array($_GET['number'],$arr2)))
   {
         $title = "OSX Yosimite";
         $title2 = "User";
   }


   echo $title;
   echo $title2;
 ?>

希望它对你有用。

基于URL显示不同的信息

5 个答案: