Question

我想找到两个日期之间缺少的日期。表格中存在一个名为date的字段

2018-11-13、2018-11-18、2018-11-20、2018-11-25

我想要从2018-11-13到2018-11-25的丢失日期

Expected Output
2018-11-14
2018-11-15
2018-11-16
2018-11-17
2018-11-19
2018-11-21
2018-11-22
2018-11-23
2018-11-24

Answer 1

您可以在下面使用递归CTE-

DECLARE  @s_date date = '2018-11-13',
         @e_date date = '2018-12-01'

;WITH cte AS (
SELECT @s_date as fdate
UNION ALL
SELECT CAST(DATEADD(day,1,fdate) as date)
FROM cte
WHERE date_ < @e_date
)

SELECT * FROM cte eft join yourtablename t2 on t1.Date=t2.date
    where t2.date is null
OPTION (MAXRECURSION 0)

或者您可以使用日历表

   DECLARE  @s_date date = '2018-11-13',
             @e_date date = '2018-12-01'

    SELECT  Date
    FROM    dbo.Calendar t1 left join yourtablename t2 on t1.Date=t2.date
    and Date >= @s_date AND Date < @e_date
    where t2.date is null

Answer 2

这肯定会起作用：

        select * from date_ranges;
        13-NOV-18
        01-DEC-18
        16-NOV-18
        20-NOV-18

        set serveroutput on;
create or replace procedure date_range( d1 date, d2 date) is 
op date;
op2 date;
diff number;
comp date;
a  number;
b number;
j number;
cursor c1 is select a from date_ranges;
begin
select d2-d1 into diff from dual;
for op in 1..diff 
loop <<forloop>>
j:=0;
select d1+op into op2 from dual;

          open c1;
          loop <<curloop>>
          fetch c1 into comp;
          if(c1%notfound) then
          exit;
          end if;
          select sysdate-to_date(comp) into a from dual;
          select sysdate-to_date(op2)  into b from dual;
          if(a=b)then 
          j:=1;
          end if;

          end loop  curloop;

          close c1;
if(j=0)then 
DBMS_OUTPUT.PUT_LINE(op2);
end if;
end loop forloop;
end;
/

declare
m date;
n date;
begin 
select min(a) into m from date_ranges;
select max(a)  into n from date_ranges;
date_range(m,n);
end;
/

输出：

14-NOV-18
15-NOV-18
17-NOV-18
18-NOV-18
19-NOV-18
21-NOV-18
22-NOV-18
23-NOV-18
24-NOV-18
25-NOV-18
26-NOV-18
27-NOV-18
28-NOV-18
29-NOV-18
30-NOV-18

因此日期16 nov和20 nov不会被打印，因为它们存在于查询表中，而缺失日期则显示在采样日期的最小值和最大值之间。谢谢!!!!!!!!!!!!!!!!!! 1

Answer 3

如果您想将丢失的日期存储在某些表中，则可以使用While循环。这样也可以工作。

Declare @mindate date ='2018-11-13' 
Declare @maxdate date = '2018-12-01' 

select '2018-11-18' as Existingdate into #tmp  --made existing dates 
create table Missingdates (Missingdate date) 

Declare @id int = 1 
While  dateadd(day, @id, @mindate) > @mindate and dateadd(day, @id, @mindate) < @maxdate  
Begin 
insert into Missingdates  select dateadd(day, @id, @mindate) as MIssingDate  where not exists (Select  * from #tmp t where t.Existingdate = dateadd(day, @id, @mindate)) 
set @id = @id+1 
end 

select * from Missingdates

输出：

Missingdate
2018-11-14
2018-11-15
2018-11-16
2018-11-17
2018-11-19
-- so on

添加了不存在子句，并且不会提供现有日期。

SQL中两个日期之间的日期丢失

3 个答案: