Question

我读到了这个，我认为这个值可能是nil，并且您不能断言nil bla bla bla，好吧，我尝试检查此sqlite3_bind_text！= sqlite_ok我尝试了防护，但似乎无济于事。请需要帮助！

func insert(_ name: String = "",_ image: String = "",_ ingredients:String = "", instructions:String = ""){
    var stmt:OpaquePointer?
    let query = "INSERT INTO Recipe (name,image,ingredients,instructions) VALUES(?,?,?,?)"
    if sqlite3_prepare(db,query, -1,&stmt,nil) == SQLITE_OK {
        sqlite3_bind_text(db, 1, name, -1, nil)
        sqlite3_bind_text(db,2,image,-1,nil)
        sqlite3_bind_text(db,3,ingredients,-1,nil)
        sqlite3_bind_text(db,4,instructions,-1,nil)
    }  
}

Answer 1

nvm解决了

sqlite3_bind_text(db, 1, name, -1, nil)
sqlite3_bind_text(db,2,image,-1,nil)
sqlite3_bind_text(db,3,ingredients,-1,nil)
sqlite3_bind_text(db,4,instructions,-1,nil)

db应该已经替换为stmt而不是dunno为什么

sqlite3_bind_text(stmt, 1, name, -1, nil)
sqlite3_bind_text(stmt,2,image,-1,nil)
sqlite3_bind_text(stmt,3,ingredients,-1,nil)
sqlite3_bind_text(stmt,4,instructions,-1,nil)

Sqlite3线程1：EXC_BAD_ACCESS（code = EXC_I386_GPFLT）错误

1 个答案: