Question

我知道许多用户都会遇到这种类型的错误，而且我确实在发布之前看到了这些帖子。但仍然没有解决我的问题的方法，希望你们能理解。...

file.php

<?php 

require_once("dbcontroller.php");
$db_handle = new DBController();


$result="SELECT * FROM do_order";
$resultorder = $db_handle->runSelectQuerys($result);

echo "<table border='1'> 
<tr> 
<th>order</th> 
<th>payment</th> 
<th>generate</th> 
<th>tracking id</th> 
</tr>"; 

while($row = mysqli_fetch_assoc($resultorder)) 

{ 
$id = $row['id']; 
echo "<tr>"; 
echo "<td>" . $row['order_id'] . "</td>"; 
echo "<td>" . $row['payment_type'] . "</td>"; 

echo "<td>"; 
if (empty($row['tracking_id'])) { 
echo "<form method='post' action='call3.php'>"; 
echo "<input type ='hidden' name='id' value='$id'> 
<input type ='hidden' name='order_id' value='".$row['order_id']."'> 
<input type ='hidden' name='entity_id' value='".$row['entity_id']."'> 
<input type='submit'> 
</form>"; 
} 
echo "</td>"; 
echo "<td>" . $row['tracking_id'] . "</td>"; 

echo "</tr>"; 
} 
echo "</table>"; 

?>

dbcontroller.php

<?php

class DBController {
    private $conn = "";
    private $host = "localhost";
    private $user = "root";
    private $password = "";
    private $database = "do_management4";

    function __construct() {
        $conn = $this->connectDB();
        if(!empty($conn)) {
            $this->conn = $conn;            
        }
    }

    function connectDB() {
        $conn = mysqli_connect($this->host,$this->user,$this->password,$this->database);
        return $conn;
    }

    function runSelectQuery($query) {
        $result = mysqli_query($this->conn,$query);
        while($row=@mysqli_fetch_assoc($result)) {
            $resultset[] = $row;
        }
        if(!empty($resultset))
            return $resultset;
    }
    function runSelectQuerys($query) {
        $result = mysqli_query($this->conn,$query);
        while($row=@mysqli_fetch_assoc($result)) {
            $resultset[] = $row;
        }       
        if(!empty($resultset))
            return $resultset[0];
    }
    function executeInsert($query) {
        //echo $query;die;
        $result = mysqli_query($this->conn,$query);
        $insert_id = mysqli_insert_id($this->conn);
        return $insert_id;

    }
    function executeUpdate($query) {
        $result = mysqli_query($this->conn,$query);
        return $result;

    }

    function executeQuery($sql) {
        $result = mysqli_query($this->conn,$sql);
        return $result;

    }

    function numRows($query) {
        $result  = mysqli_query($this->conn,$query);
        $rowcount = mysqli_num_rows($result);
        return $rowcount;
    }
}
?>

错误：

警告：mysqli_fetch_assoc（）期望参数1为mysqli_result，
中给出的数组

我正在使用mysqli。...

请让我知道是否需要更多详细信息。...

请帮助我找到解决方法。...

预先感谢。...

得到警告：mysqli_fetch_assoc（）期望参数1为mysqli_result

0 个答案: