Question

我的代码中有关于mysql_fetch_assoc（）的警告，但我认为代码很好

    <?php
        $con = mysqli_connect("localhost","root","","profiles");
        $q = mysqli_query($con,"SELECT * FROM users");
        while($row = mysqli_fetch_assoc($q)){
            echo $row['username'];
            if($row['image'] == ""){
                echo "<img width='100' height='100' src='pictures/default.jpg' alt='Default Profile Pic'>";
            } else {
                echo "<img width='100' height='100' src='pictures/".$row['image']."' alt='Profile Pic'>";
            }
            echo "<br>";
        }
    ?>

Answer 1

这意味着您的查询失败。这里的明智之举是检查你的查询是否返回false，如下所示：

if(!$q){
  die("Error in query:". mysqli_error($con));
}

Answer 2

首先，你必须检查错误。

<html>
<head>
   
<body>

<div class="parallax">
  <div class="parallax_group">
    <div class="parallax_layer parallax_layer--back">
      <p>Back Layer</p>
    </div>

    <div class="parallax_layer parallax_layer--base">
      <p>Base Layer</p>
    </div>

    <div class="parallax_layer parallax_layer--deep">
      <p>Deep Layer</p>
    </div>
  </div>

<div class="static_content">

</div>
</div>
   </body>
   </html>

警告：mysqli_fetch_assoc（）期望参数1为mysqli_result，boolean

2 个答案: